PDA

View Full Version : Gravitational Force


DarkIndiglo
Nov25-05, 08:14 PM
See Attached Word Document :smile:

Integral
Nov25-05, 09:36 PM
This is pretty trivial algebra. If you are having trouble with this you need to find some help with your math.


F_g = \frac {G M_1 M_2} {r^2}

I will do r^2 for you, you should be able to puzzle out the rest.
Multiply both sides by r^2
F_g r^2 = \frac {G M_1 M_2 r^2} {r^2}

Cancel the r^2 in the Right hand side.

F_g r^2 = G M_1 M_2

Now divide both sides by F_g

\frac {F_g r^2 } {F_g} = \frac {G M_1 M_2} {F_g}

Now cancel the F_g in the Left hand side to get

r^2 = \frac {G M_1 M_2} {F_g}

Similar operations will isolate the other quantities you need.

DarkIndiglo
Nov26-05, 06:34 PM
Hehe
Thanks alot, I just couldn't seem to rearrange this :rofl: