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View Full Version : Second quantization (here abusive)


kleinwolf
Dec2-05, 02:32 AM
Let's take a qbit, normally described by a unit vector in R^2 : (cos(phi),sin(phi)).

The quatization comes from the fact that the outcome of measurement if either phi=pi*n (0 or -1 for example) or phi=pi/2+pi*m (1 for example).

Usually phi is continuous. However it can be quantized if for example phi is computed out of average over previous outcomes, or does this make no sense at all ?