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I have decided to post an exercise and see what happens. You can post your own problems, too, if you wish. Have fun with this one!
Solve the following differential equation:
y′′′ = y
arcnets
Apr11-03, 04:07 PM
y(t) = a*exp(b*t) where b^3 = 1.
The general solution is of the form
y(x)=c1*exp(q1*x)+c2*exp(q2*x)+c3*exp(q3*x)
where c1, c2 and c3 are (complex) constant that can be fixed by initial conditions and
q1=1
q2=(-1+i*sqrt(3))/2
q3=(-1-i*sqrt(3))/2
This can be re-written in the real field as
y(x)=exp(x)* c1 + A*exp(-x/2)*cos(sqrt(3)*x+B) )
where A and B are new constants depending on c2 and c3 only.
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