Physics

[mustang]

Problem 12.
Four charged particles are placed so that each particle is at the corner of a square. The sides of the square are 13 cm. The charge at the upper left corner 3.6 uC, the charge at upper right corner -6.5 uC, the charge at lower left corner, and the charge at the lower right corner is -9.1 uC.
What is the direction of the force (measured from the positive x-axis, with counterclockwise positive)? Answer in degrees.
Note: Would the answer be -90 or 90?

[ShawnD]

That question has no answer since you are given no point of referance.

[himanshu121]

Force will be different at different points

Pls specify the points were it is to be found

u can choose ur reference frame with origin at any charge

Write the field equation at the point u want to calculate in vector form in i,j components
arctan(theta)=coeff of j/coeff of i
Will give u direction
u can yourself infer in which Quadrant the point lies thereby deciding whether the angle is obtuse or acute or 90 deg

[Doc Al]

Originally posted by mustang
What is the direction of the force (measured from the positive x-axis, with counterclockwise positive)?
The force on what?