Cyrus
Apr5-06, 12:35 AM
I have to solve this problem for a circuit. Its a capacitor, a resistor and another capacitor all in series.
Both capacitances are the same, 1uF, and the resistor is 100k-Ohm.
I have to find the current function of time.
What I did was use KVL to get:
- \frac{1}{c_1} \int i(t)dt + v_1 (t_0) + \frac{1}{c_2} \int i(t)dt + v_2 (t_0) + R i(t) = 0
Then I took the derivative to get:
- \frac{1}{c_1} i(t) + R \frac {di}{dt} + \frac{1}{c_2}i(t) =0
Which simplifies to:
R( \frac{1}{c_2} - \frac {1}{c_1} )^{-1} i(t) + \frac {di}{dt} = 0
But the two capacitances have the same value, which means that RC-eq is zero. That's wrong....hmmmmmmmmm
Both capacitances are the same, 1uF, and the resistor is 100k-Ohm.
I have to find the current function of time.
What I did was use KVL to get:
- \frac{1}{c_1} \int i(t)dt + v_1 (t_0) + \frac{1}{c_2} \int i(t)dt + v_2 (t_0) + R i(t) = 0
Then I took the derivative to get:
- \frac{1}{c_1} i(t) + R \frac {di}{dt} + \frac{1}{c_2}i(t) =0
Which simplifies to:
R( \frac{1}{c_2} - \frac {1}{c_1} )^{-1} i(t) + \frac {di}{dt} = 0
But the two capacitances have the same value, which means that RC-eq is zero. That's wrong....hmmmmmmmmm