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phd15@phys.keele.ac.uk
May4-06, 05:00 AM
my question concerns two photon annihilation in the lab frame.

a positron and an electron annihilate resulting in photon1 and photon2,
such that
e+ + e- -> gamma1 + gamma2

below respectively,

p+,p- are the positron,electron momenta
k1,k2 are photon 1,2 k-vectors
omega 1,2 are the photon 1,2 frequencies
m is the mass of the electron,positron
E+,E- are the positron,electron energies
Ef is the energy of the final state (after annhiliation)
d{}/d{} represents the partial derivative wrt the contents of the
brace in the denominator
A^n denotes A to the power n
|p| denotes modulus p ie (p^2)^(1/2)

in the lab fame the momentum of the electron is given by
p- = (0,0,0,im), where i=sqrt(-1)

given the kinematical relations

|p+ - k1| = Sqrt(|p+|^2 - 2 |p+|omega1 cos theta1 + omega1^2)
= |k2|
= omega2
and
m + E+ omega1 + omega2

where
(d{Ef}/d{|k1|}) = d{omega1 + |p+ - k1|}/d{|k1|}
= 1 + (|k1| - |p+| cos theta1)/omega2
= m(m + E+)/(omega1 omega2)

Can anyone explain the final equality ? incidentally if anyone has
Sakurai Advaced QM this is on page 217 eq. (4.183) & (4.184)

Any help on this is greatly appreciated
Zak