What Is the Mass of the Piston in a Vertical Cylinder with Air at 100C?

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Homework Help Overview

The problem involves a vertical cylinder with a frictionless piston containing air at 100°C. The challenge is to determine the mass of the piston given the ambient pressure, cylinder volume, and mass of the air. Participants are exploring the implications of pressure and forces acting on the piston.

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  • Mixed

Approaches and Questions Raised

  • Participants discuss the forces acting on the piston, including atmospheric pressure and the pressure of the air inside the cylinder. There is a focus on the equilibrium condition of the piston and the need to calculate the internal pressure accurately. Some participants question the assumption of the piston's motion, considering whether it can be assumed to be at rest.

Discussion Status

The discussion is ongoing, with participants providing insights into the forces at play and suggesting that the piston may be in equilibrium. There is an emphasis on calculating the internal pressure and understanding the balance of forces without reaching a definitive conclusion.

Contextual Notes

Participants note the importance of correctly interpreting the dimensions of the cylinder and the need for clarity in the calculations related to pressure and forces. There is a mention of the ideal gas law as a potential approach to finding the internal pressure.

seang
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This is problem one on my worksheet, and all the rest I've found to be easier, so I'm thinking I'm missing something here:

A vertical cylinder fitted with a frictionless piston contains air at 100C The piston has an unknown m and a diameter of .150mm, and the ambient pressure outside the cylinder is 101kPa. If the cylinder volume is 500 liters and the mass of the air is 5kg, what is the piston mass, m?

I calculated the pressure inside the cylinder and it is huge. That means the piston would accelerate upwards. Since the sum of the forces on the piston must equal its mass times acceleration, I used something like (AFTER i had obtained the inner pressure):

p(sys)*a(piston) - p(ambient)*a(piston) - mass(piston)*gravity = mass(piston)*acceleration(piston)

The trouble is, is that i know neither the acceleration or the mass of the piston. THe only way this can work is if I assume that the piston is not moving, but I don't think I can just assume that?
 
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seang said:
This is problem one on my worksheet, and all the rest I've found to be easier, so I'm thinking I'm missing something here:

A vertical cylinder fitted with a frictionless piston contains air at 100C The piston has an unknown m and a diameter of .150mm, and the ambient pressure outside the cylinder is 101kPa. If the cylinder volume is 500 liters and the mass of the air is 5kg, what is the piston mass, m?

I calculated the pressure inside the cylinder and it is huge. That means the piston would accelerate upwards. Since the sum of the forces on the piston must equal its mass times acceleration, I used something like (AFTER i had obtained the inner pressure):

p(sys)*a(piston) - p(ambient)*a(piston) - mass(piston)*gravity = mass(piston)*acceleration(piston)

The trouble is, is that i know neither the acceleration or the mass of the piston. THe only way this can work is if I assume that the piston is not moving, but I don't think I can just assume that?
I don't see anything that suggests it is moving so assume it is at rest. What is the force on the piston at rest? So the weight + atmospheric pressure x area has to equal the pressure inside the cylinder x area. The key is figuring out the pressure inside the cylinder. Show us how you are calculating that.

Note: the area of the cylinder must be .150 m, not .150 mm.

AM
 
Last edited:
Using Ideal gas law: Psys = ((5kg)(287J)(373K))/.5m^3
 
The idea is to assume that the piston is in equilibrium. The piston experiences three forces:

its weight downwards [itex]W[/itex]
the downwards force on it due to atmospheric pressure pushing on it [itex]p_a[/itex]
and the upwards force due to the pressure of the air inside of it [itex]p_i[/itex]

these three forces need to cancel out.
 

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