View Full Version : Force of Friction Equation?
paigegail
Jan26-04, 09:57 PM
I think the reason that my problems have arisen is because of my equation for the force of friction. I have
Ff= ucosAngle
That right?
The force due to friction:
F = \mu N = \mu m g
Where \mu is the coefficient of friction (either static of kinetic), and N is the normal force. On a horizontal plane, the normal force is just the weight of the object, which is mg.
- Warren
kishtik
Jan29-04, 09:38 AM
And to include the angle;
F_f=\mu mg cos \alpha
himanshu121
Jan29-04, 11:33 AM
It is the limiting force of friction or say max friction force exerted and f force due to friction depends on the circumstance
For eg moving on a plane surface Chroots Ans is correct and in case if body is on inclined surface Kishtiks Ans is correct
kishtik
Jan30-04, 03:10 AM
Originally posted by himanshu121
For eg moving on a plane surface Chroots Ans is correct and in case if body is on inclined surface Kishtiks Ans is correct
I love my equation. What is the angle for a plane surface? 0? Then what is cos0? 1? Then what is 1.mu mg? mu mg? Are the two eqs the same?[:)]
PrudensOptimus
Jan30-04, 08:52 AM
Originally posted by himanshu121
It is the limiting force of friction or say max friction force exerted and f force due to friction depends on the circumstance
For eg moving on a plane surface Chroots Ans is correct and in case if body is on inclined surface Kishtiks Ans is correct
lol rofl same eq man.
himanshu121
Jan30-04, 09:25 AM
It is not same equation
It is the case of the equation under the given conditions only
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