Why Is Charge Measured in Nanofarads Instead of Coulombs?

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SUMMARY

The discussion clarifies the measurement of electric charge using the formula Q = CV, where Q represents charge, C is capacitance in Farads, and V is voltage in volts. A common point of confusion arises from the conversion of units, as the charge is calculated in nanocoulombs (nC) rather than nanofarads (nF). Specifically, the calculation provided in the lab handout demonstrates that 4.7 nanofarads (nF) multiplied by 30 volts results in 141 nanocoulombs (nC), confirming that charge is indeed measured in coulombs, not farads.

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AngelofMusic
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Hello,

We haven't covered capacitance in class yet, but our lab involves the use of capacitors, so I thought I'd throw out a general question.

We were asked to use the MOS FET Electrometer to measure charge, and we were given the formula:

Q = CV

Where C is the capacitance, and V is the potential difference. C is measured in Farads and V in volts.

I'm just confused because in the sample calculations provided by the lab handout, we had:

Qinit = CV = 4.7x10^-9 [F] X 30 [V] = 141 [nF]

How come the unit for charge ended up being in nanofarads, and not in coulombs or nanocoulombs or anything like that?

Any clarifications would be appreciated!
 
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That has to be a typo.

1 Farad is defined as 1 Coul./Volt

You have 4.7 nF x 30 V = 141 nC
 
Okay, that makes a lot more sense.

Thanks!
 

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