NINHARDCOREFAN
Feb3-04, 07:36 PM
An electron and a proton are each placed at
rest in an electric field of 735 N/C. Calculate the velocity of each particle 44.3 ns after being released, and denote the direction parallel to the field as positive.
What is the velocity of the electron? Answer in units of m/s.
Given: q= 1.6e-19, m=9.1e-31
Ok, I did this:
a= qE/m
V= at
V= qE/m *t
V= 1.6e-19*735/9.1e-31 * 44.3e-9
V= 5.72492e+06
But it's wrong, anyone know why?
rest in an electric field of 735 N/C. Calculate the velocity of each particle 44.3 ns after being released, and denote the direction parallel to the field as positive.
What is the velocity of the electron? Answer in units of m/s.
Given: q= 1.6e-19, m=9.1e-31
Ok, I did this:
a= qE/m
V= at
V= qE/m *t
V= 1.6e-19*735/9.1e-31 * 44.3e-9
V= 5.72492e+06
But it's wrong, anyone know why?