How Is Magnetic Field Generated by a Stream of Protons?

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The discussion focuses on calculating the magnetic field generated by a stream of protons passing at a rate of 10^9 protons/second, specifically 2.0 meters from the beam. The correct formula to use is B = (μ0 * I) / (2 * π * r), where μ0 is the permeability of free space (4π x 10^-7 Tm/A), I is the current calculated as 1.6 x 10^-19 C multiplied by 10^9 protons/second, and r is the distance from the beam (2.0 m). The resulting magnetic field is calculated to be 6.4 x 10^-11 Tesla, which, while small, is measurable and can influence nearby objects.

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A stream of protons passes a given point in space at a rate of 10 E9 protons/second. What mafnetic fiel do they produce 2.0 m from the beam?
i think i would use
I= 1.6 E-19x10 E 9
and then
B=(permativity of free space x I)/(2pir) using 2.0 as r? am i totally off or close?
 
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permittivity of free space = ε0 = 8.85 x 10-12 C2/Nm2

permeability of free space = μ0 = 4Π x 10-7 Tm/A

Are those close, or totally off?

In this case, you want μ0 (permeability), not ε0.
 


Your approach is correct. The magnetic field produced by a stream of protons can be calculated using the formula B = (μ0 * I) / (2 * π * r), where μ0 is the permeability of free space, I is the current (in this case, the rate of protons passing a point per second), and r is the distance from the beam.

Plugging in the values given in the question, we get B = (4π * 10^-7 * 1.6 * 10^-19 * 10^9) / (2 * π * 2.0) = 6.4 * 10^-11 Tesla. This is a very small magnetic field, but it is still measurable and can have an effect on nearby objects.
 

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