View Full Version : function's period
wormhole
Feb13-04, 01:22 PM
i have this function(taken from fourier analysis):
n - 1,2,3...
f(x) = cos( (2*pi*n)/L * x )
the literature says this function has L period (n parameter):
f(x + L) = cos( (2*pi*n)/L * (x + L) ) =
= cos( 2*pi*n/L * x + 2*pi*n) = cos( 2*pi*n/L * x)
so it's true that L f's period for any n.....
but L/n is also f's period because:
f(x + L/n) = cos( (2*pi*n)/L * (x + L/n) ) =
= cos( 2*pi*n/L * x + 2*pi) = cos( 2*pi*n/L * x)
so what happens here??
matt grime
Feb13-04, 01:47 PM
n varies, and as there is no summation there, one only conclude that when you treat f as unique, rather than a family of functions, one for each n, that you might have misread the literature
wormhole
Feb13-04, 01:57 PM
actually there is a summation over n
it is just one term from fourier series...
matt grime
Feb13-04, 02:06 PM
So, you need to know why
\sum_n b_n\cos(2\pi nx/L)
has period L and not L/n? Erm, is because n varies not an acceptable anwer?
It doesnt't matter that each individual term may have period less than L, only that the sum has period L.
And assuming b_n are such that that sum makes sense obviously
wormhole
Feb13-04, 03:00 PM
you might have misread the literature
you are right...[:)] (too much reading)
thank you very much
wormhole
Feb13-04, 06:33 PM
i want to rephrase what i asked before
lets take this function,
f(x)=cos(2*pi*3/L*x)
n is parameter and lets say n=3 so f(x) becomes
f(x)=cos(2*pi*3/L*x)
as i said earlier both numbers L/3 and L
are sutisfying the following condition
(#) f(x + T)=f(x): T f's period
or to be more specific
f(x + L)=f(x) and f(x + L/3)=f(x)
I asked how it can be that both equilities are true...
Meanwhile it occured to me that this condition (#) alone doesn't says
that T is a period and if we want T to be a period we must demand
that T is also minimal number for which (#) holds
so the answer to my original question is that f's period is L/n
Is what i wrote is correct?
matt grime
Feb13-04, 06:37 PM
cos(x) has period 2pi
cos(kx) has period 2pi/k for every k in R
that enough?
wormhole
Feb13-04, 06:47 PM
cos(kx) has period 2pi/k
you mean that cos(kx) has a period 2*p/k?
but what about what i said before that?
...that period is defined by:
1) f(x+L)=f(x)
2) L is minimal among all other numbers
is that correct?
matt grime
Feb13-04, 07:05 PM
yep that looks about right. wolfram's mathworld is your friend for these things
Organic
Feb13-04, 07:17 PM
Hi wormhole,
Let us say that L or L/n are circle's radius.
So, in both cases you have f(x+circle)=f(x)
wormhole
Feb13-04, 07:36 PM
thanks guys for your help[:)]
no more question...
matt grime
Feb14-04, 04:29 AM
Originally posted by Organic
Hi wormhole,
Let us say that L or L/n are circle's radius.
So, in both cases you have f(x+circle)=f(x)
Erm, we could say that, but it would be wrong.
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