15

[NINHARDCOREFAN]

https://hw.utexas.edu/tmp/Muddam1/1077041275Xuj.pdf

Ok for #15, to find work I did this


q_1 = -6*10^-6
q_2 = 1*10^-5
q_3 = -1.1*10^-5


W = k(q_1*q_2/4 + q_1*q_3/7 + q_2*q_3/sqrt(65)

And I got -.172745091 as an answer but it's wrong, why?

By accident I created a new topic, instead of posting a reply my last topic.

[Doc Al]

Originally posted by NINHARDCOREFAN
W = k(q_1*q_2/4 + q_1*q_3/7 + q_2*q_3/sqrt(65)

What's that last term supposed to be?

I presume, for some reason, you are not doing #12 & #13? Just like #14 follows immediately from #12, #15 follows from #13.

In any case, the work done to move two charges from infinity to a distance r apart is: \frac{kq_1q_2}{r}. There will only be two terms.

[NINHARDCOREFAN]

There will only be two terms.

This made me realize what I did wrong, thanks.


I presume, for some reason, you are not doing #12 & #13? Just like #14 follows immediately from #12, #15 follows from #13.

I already did all the previous problems before asking for help.

[Doc Al]

Originally posted by NINHARDCOREFAN
I already did all the previous problems before asking for help.
Then I hope you realize you are doing twice the work. [:)]

For example, #12 asks for the field at the origin and #14 asks for the force on a charge at the origin.

If the answer to #12 is E, the answer to #14 is just Eq.

But, no problem. Doesn't matter if you do it twice, as long as you do it right.

[NINHARDCOREFAN]

Then I hope you realize you are doing twice the work.

For example, #12 asks for the field at the origin and #14 asks for the force on a charge at the origin.

If the answer to #12 is E, the answer to #14 is just Eq.

But, no problem. Doesn't matter if you do it twice, as long as you do it right


Damn, should have realized that work is electric field.