Calculate the magnitude of the tension force in the rope

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Homework Help Overview

The discussion revolves around calculating the tension force in a rope used to pull a car and the force exerted by brakes during deceleration. The subject area includes dynamics and Newton's laws of motion.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of Newton's second law (F=ma) to determine forces involved in both problems. There are attempts to calculate initial velocities and forces, with some questioning the assumptions made in the calculations.

Discussion Status

Participants are actively engaging with the problems, sharing insights and calculations. Some guidance has been offered regarding the approach to finding initial velocities and forces, though no consensus has been reached on the correctness of the original poster's answer.

Contextual Notes

Assumptions such as ignoring friction and the nature of the braking force are under discussion, with participants exploring the implications of these assumptions on their calculations.

psruler
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Can anyone help me on two problems of my hw?

1) A tow rope is used to pull a 1050-kg along a level road, initially accelerating it from rest at 1.50m/s^2 for a duration of 12.0seconds. Calculate the magnitude of the tension force in the rope during this acceleration.(ignore friction in the problem)

My answer was 394N but i want to make sure if that was correct.

2) As a stoplight is approached, the person riding in the towed car applies the brakes and brings it to a stop in an additional 5.00s. Calculate the magnitude of the force of the brakes on the car, assuming the brakes are applied evenly so that the deceleration is constant.
 
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Regarding question 1:

This is clearly an "F=ma" question. A mass of 1050 KG and an acceleration 1.5 m/s^2should give a force of at least 1500N

Question 2:
There's a bunch of ways to do this one. One of the easiers ways is to use v=at to find the starting velocity, and then the force in a similar fashion. Clearly the force here is larger than the force for question 1.
 
Ok, I got the initial velocity for ques.2 and where do I go from there?
 
The change in velocity is equal to the acceleration multiplied by the time. You know the change in velocity, and the time, so that should give you the acceleration.
 
wouldn't that give me an acceleration of 1.5 again?
 
Ok i got it. thanks NateTG for your help!
 

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