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VVill
Jan19-07, 05:43 PM
1. The problem statement, all variables and given/known data
http://img174.imageshack.us/img174/9323/physsh5.png (http://imageshack.us)


2. Relevant equations

v=sqrt(T/mu) f=2Lv

3. The attempt at a solution

v=sqrt (10*9.8)/(.8/2.7)
v=330.75

f=330.75*1.6447*2
f=1087 * 10 <-(10 is the number of nodes)

f=10879 Hz

:frown:

OlderDan
Jan20-07, 08:51 AM
The tension in the wire will be uniform, but the velocity of the wave will be different in the two different materials. The frequency will be that same in both parts. The wavelengths are determined by the condition that the joint is a node.