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MrDMD83
Feb27-07, 10:47 PM
1. The problem statement, all variables and given/known data

Suppose the minimum uncertainty in the position of a particle is equal to its de Broglie wavelength. If the particle has an average speed of 4.7 105 m/s, what is the minimum uncertainty in its speed?

2. Relevant equations

lambda=h/p & (Py)(Y) is greater than or equal to h/4pi

3. The attempt at a solution

I'm not really sure where to start

mikemillenium
Sep14-08, 10:48 PM
Let LAMDA = De Broglie Wavelength
DELTAp = uncertainty in linear momentum
DELTAy = uncertainty in position
DELTAv = uncertainty in speed

(Question gives:) DELTAy = LAMDA
Since DELTAp*DELTAy = h/(4pi), then DELTAp*LAMDA = h/(4pi)
Thus, LAMDA = h/(4pi*DELTAp)

Also, LAMDA = h/p

Combine the 2: h/(4pi*DELTAp) = h/p
So: 4pi*DELTAp = p

p = mv, DELTAp = m*DELTAv
4pi*m*DELTAv = mv
4pi*DELTAv = v

We want DELTAv, so:
DELTAv = v/(4pi)

tada.

stepuckey
Nov17-08, 12:04 AM
oh man, delta p=m*delta v was the whole key to figuring this out that I NEVER would have thought of. Thank you so much for this detailed solution!! You are the master :)