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gulsen
Apr18-07, 12:30 PM
In Feynman lectures in physics v2 28-6, Feynman points out that we can add a constant times \phi to D'Alembertian without distrupting the relativistic invariance. How and why?? Can someone work out a mathematical proof?

Thanks in advance.

lalbatros
Apr18-07, 02:14 PM
The sum of two invariant quantities is an invariant quantity.

Mentz114
Apr19-07, 10:20 PM
The derivative of a constant wrt any variable is zero.