tpm
May8-07, 01:59 PM
But..is really so easy? (Möbius inversion), let be F(x) and G(x) functions
F(x)= G(ax)+G(2ax)+G(3ax)+...............
for n=,1,2,3,4,5,............ a is a fixed real number. then
G(ax)= \sum_{n=1}^{\infty}\mu (x) F(nx)
is seems too easy for me, to be true.
F(x)= G(ax)+G(2ax)+G(3ax)+...............
for n=,1,2,3,4,5,............ a is a fixed real number. then
G(ax)= \sum_{n=1}^{\infty}\mu (x) F(nx)
is seems too easy for me, to be true.