Garen
Sep19-07, 07:02 PM
1. The problem statement, all variables and given/known data
Going over examples of continuity and asymptotes in class, we came across this function:
f(x) = 6sin(x) / (√X)
I know that the numerator is bounded between -1 and 1, and that the denominator increases to infinity. But, my question is...what would be the horizontal asymptote(s) if the equation had been:
f(x) = tan(x) / (√X)
3. The attempt at a solution
I tried finding the limit both graphically and numerically, and failed to come to any solid conclusion.
http://i186.photobucket.com/albums/x79/garenzy/GRAPH.jpg
Looking at the data table even at intervals in the hundreds of thousandths didn't help.
http://i11.tinypic.com/4lyic00.jpg
When I tried analytically I became lost. I know that if the numerator increases faster than the numerator then the horizontal asymptote dne. I also am aware that if the denominator increases faster than the numerator, then the asymptote is 0. But since a tangent function isn't bounded by any limits, like a sinusoid function, I'm not sure how to figure this out.
Going over examples of continuity and asymptotes in class, we came across this function:
f(x) = 6sin(x) / (√X)
I know that the numerator is bounded between -1 and 1, and that the denominator increases to infinity. But, my question is...what would be the horizontal asymptote(s) if the equation had been:
f(x) = tan(x) / (√X)
3. The attempt at a solution
I tried finding the limit both graphically and numerically, and failed to come to any solid conclusion.
http://i186.photobucket.com/albums/x79/garenzy/GRAPH.jpg
Looking at the data table even at intervals in the hundreds of thousandths didn't help.
http://i11.tinypic.com/4lyic00.jpg
When I tried analytically I became lost. I know that if the numerator increases faster than the numerator then the horizontal asymptote dne. I also am aware that if the denominator increases faster than the numerator, then the asymptote is 0. But since a tangent function isn't bounded by any limits, like a sinusoid function, I'm not sure how to figure this out.