ace214
Nov18-07, 09:07 PM
A stone is dropped from rest into a well. The sound of the splash is heard exactly 1.70 s later. Find the depth of the well if the air temperature is 12.0°C.
Anything _s is the sound wave, anything _f is the stone falling
I tried using these equations:
v_s = 331(sqrt(285/273) = 338.2
t_s = x/338.2
1.7 = t_s + t_f
x = .5(9.8)t_f^2
I plugged the first equation into the second, solved the second for t_f and plugged that into the last one. Ends up being a nasty quadratic but I'm pretty sure my math is ok. I ended up with
.000042841x^2 - .0492x + 14.161
but that gives imaginary solutions. Thanks for the help.
EDIT: Nevermind- I forgot to move the x over. Sorry!!!!!!!!!!!
Anything _s is the sound wave, anything _f is the stone falling
I tried using these equations:
v_s = 331(sqrt(285/273) = 338.2
t_s = x/338.2
1.7 = t_s + t_f
x = .5(9.8)t_f^2
I plugged the first equation into the second, solved the second for t_f and plugged that into the last one. Ends up being a nasty quadratic but I'm pretty sure my math is ok. I ended up with
.000042841x^2 - .0492x + 14.161
but that gives imaginary solutions. Thanks for the help.
EDIT: Nevermind- I forgot to move the x over. Sorry!!!!!!!!!!!