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Hello. I'm learning tensor analysis. I have a problem. We know that
\Gamma^i_{jk}=\vec{\epsilon^i}\cdot\frac{\partial\ vec{\epsilon_j}}{\partial q^k}
Please prove the relation
\frac{\partial\vec{\epsilon_j}}{\partial q^k}=\Gamma^m_{jk}\vec{\epsilon_m}
Thanks very much in advance
belliott4488
Jan6-08, 10:48 AM
What'll you pay me?
hanskuo
Jan21-08, 11:58 PM
Hello. I'm learning tensor analysis. I have a problem. We know that
\Gamma^i_{jk}=\vec{\epsilon^i}\cdot\frac{\partial\ vec{\epsilon_j}}{\partial q^k}
Please prove the relation
\frac{\partial\vec{\epsilon_j}}{\partial q^k}=\Gamma^m_{jk}\vec{\epsilon_m}
Thanks very much in advance
\Gamma^m_{jk}\vec{\epsilon_m}\cdot\vec{\epsilon^i}
=\Gamma^m_{jk}\delta^i{}_m=\Gamma^i_{jk}
Thanks hanskuo.
I knew this proof, but I thought that it is only correct for the inverse relation. I was wrong!
hanskuo
Jan24-08, 02:25 AM
you are wellcome, Arham
Now I'm learning Differential Geometry,too.
do you begin to lerane covariant derivatives or not ?
I'm an undergraduate physics student, hanskuo. I am learning tensor analysis from George Arfken's book. As you know, this book has a brief introduction to Covariant Derivative; I have read it. But I should do more exercises and read more about it in future.
hanskuo
Jan24-08, 11:39 AM
There are a lot of things interesting for covariant derivatives.
your original question likes this:
\nabla_{e_i}e_j=\Gamma^k{}_{ij}e_k
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