aquamarine08
Jan13-08, 06:18 PM
1. The problem statement, all variables and given/known data
Use the components method to solve this problem.
A river is flowing at 1.75 m/s. The river is 820m wide. You are on a boat that is going dock on the other side of the river, and 940 m upstream. If you need to get to the other dock in 10 minutes, what must the speed of the boat be with respect to the water?
2. Relevant equations
d_{1}=d_{0}+\frac{1}{2}t(V_{1}+V_{0})
3. The attempt at a solution
Well i assumed that (as can be seen in my attached picture) the boat was moving in a diagonal direction, so I knew that it would be moving in both the "x" and "y" direction.
x
d_{1}=d_{0}+\frac{1}{2}t(V_{1}+V_{0})
940m= 0+\frac{1}{2}(600s)(V_{1}+0)
3.13=V_{1}
y
d_{1}=d_{0}+\frac{1}{2}t(V_{1}+V_{0})
820m= 0+\frac{1}{2}(600s)(V_{1}+1.75m/s)
.98=V_{1}
3.13+.98= 4.11m/s = V_{1}
Can someone please tell me if this method is correct?? If not, please explain. Thanks so much!
Use the components method to solve this problem.
A river is flowing at 1.75 m/s. The river is 820m wide. You are on a boat that is going dock on the other side of the river, and 940 m upstream. If you need to get to the other dock in 10 minutes, what must the speed of the boat be with respect to the water?
2. Relevant equations
d_{1}=d_{0}+\frac{1}{2}t(V_{1}+V_{0})
3. The attempt at a solution
Well i assumed that (as can be seen in my attached picture) the boat was moving in a diagonal direction, so I knew that it would be moving in both the "x" and "y" direction.
x
d_{1}=d_{0}+\frac{1}{2}t(V_{1}+V_{0})
940m= 0+\frac{1}{2}(600s)(V_{1}+0)
3.13=V_{1}
y
d_{1}=d_{0}+\frac{1}{2}t(V_{1}+V_{0})
820m= 0+\frac{1}{2}(600s)(V_{1}+1.75m/s)
.98=V_{1}
3.13+.98= 4.11m/s = V_{1}
Can someone please tell me if this method is correct?? If not, please explain. Thanks so much!