View Full Version : quantum gravity
alistair
Apr17-04, 05:07 AM
<jabberwocky><div class="vbmenu_control"><a href="jabberwocky:;" onClick="newWindow=window.open('','usenetCode','toolbar=no, location=no,scrollbars=yes,resizable=yes,status=no ,width=650,height=400'); newWindow.document.write('<HTML><HEAD><TITLE>Usenet ASCII</TITLE></HEAD><BODY topmargin=0 leftmargin=0 BGCOLOR=#F1F1F1><table border=0 width=625><td bgcolor=midnightblue><font color=#F1F1F1>This Usenet message\'s original ASCII form: </font></td></tr><tr><td width=449><br><br><font face=courier><UL><PRE>The following discussion is based on the idea that a hydrogen atom\nabsorbs\na photon.\nUsing the Newtonian idea that acceleration= (v1 -v2)/t\nand mvr = nh/2pi from Niels Bohr we can write:\nacceleration=(n1/m1r1 – n2/m2r2) ( h / 2pi ) / t\nsubstituting Bohr radius equation r = 4piE0 n^2h^2/me^2 we get:\nacceleration = q^2/ 8 pi^2E0 h / t [ 1/n1 – 1/n2 ]\nIn other words an equation describing an electron\'s acceleration,\nthat is independent of wavelength or mass.Just what an equation\ndescribing an accelerating mass should be like in Newtonian\ngravitational theory.\nThe question arises:is this a route into quantum gravity?\n\n</UL></PRE></font></td></tr></table></BODY><HTML>');"> <IMG SRC=/images/buttons/ip.gif BORDER=0 ALIGN=CENTER ALT="View this Usenet post in original ASCII form"> View this Usenet post in original ASCII form </a></div><P></jabberwocky>The following discussion is based on the idea that a hydrogen atom
absorbs
a photon.
Using the Newtonian idea that acceleration= (v1 -v2)/t
and mvr = nh/2pi from Niels Bohr we can write:
acceleration=(n1/m1r1 – n2/m2r2) ( h / 2pi ) / t
substituting Bohr radius equation r = 4piE0 n^{2h}^2/me^2 we get:
acceleration = q^2/ 8 \pi^2E0 h / t [ 1/n1 – 1/n2 ]
In other words an equation describing an electron's acceleration,
that is independent of wavelength or mass.Just what an equation
describing an accelerating mass should be like in Newtonian
gravitational theory.
The question arises:is this a route into quantum gravity?
Ian Taylor
Apr18-04, 03:51 AM
<jabberwocky><div class="vbmenu_control"><a href="jabberwocky:;" onClick="newWindow=window.open('','usenetCode','toolbar=no, location=no,scrollbars=yes,resizable=yes,status=no ,width=650,height=400'); newWindow.document.write('<HTML><HEAD><TITLE>Usenet ASCII</TITLE></HEAD><BODY topmargin=0 leftmargin=0 BGCOLOR=#F1F1F1><table border=0 width=625><td bgcolor=midnightblue><font color=#F1F1F1>This Usenet message\'s original ASCII form: </font></td></tr><tr><td width=449><br><br><font face=courier><UL><PRE>alistair@goforit64.fsnet.co.uk (alistair) wrote in message news:<861c1b21.0404160430.42e4ff14@posting.google. com>...\n> The following discussion is based on the idea that a hydrogen atom\n> absorbs\n> a photon.\n> Using the Newtonian idea that acceleration= (v1 -v2)/t\n> and mvr = nh/2pi from Niels Bohr we can write:\n> acceleration=(n1/m1r1 ? n2/m2r2) ( h / 2pi ) / t\n> substituting Bohr radius equation r = 4piE0 n^2h^2/me^2 we get:\n> acceleration = q^2/ 8 pi^2E0 h / t [ 1/n1 ? 1/n2 ]\n> In other words an equation describing an electron\'s acceleration,\n> that is independent of wavelength or mass.Just what an equation\n> describing an accelerating mass should be like in Newtonian\n> gravitational theory.\n> The question arises:is this a route into quantum gravity?\n\nWhat does the acceleration that you calculate mean ? When the hydrogen\natom absorbs a photon of appropriate energy, the electron moves to a\nhigher energy level. Therefore the wavefunction of the state changes.\nHowever, you can\'t understand the hydrogen atom by assuming the\nelectrons are particles ! That is the whole point of solving the\nSchrodinger wave equation.\n\n</UL></PRE></font></td></tr></table></BODY><HTML>');"> <IMG SRC=/images/buttons/ip.gif BORDER=0 ALIGN=CENTER ALT="View this Usenet post in original ASCII form"> View this Usenet post in original ASCII form </a></div><P></jabberwocky>alistair@goforit64.fsnet.co.uk (alistair) wrote in message news:<861c1b21.0404160430.42e4ff14@posting.google.com>...
> The following discussion is based on the idea that a hydrogen atom
> absorbs
> a photon.
> Using the Newtonian idea that acceleration= (v1 -v2)/t
> and mvr = nh/2pi from Niels Bohr we can write:
> acceleration=(n1/m1r1 ? n2/m2r2) ( h / 2pi ) / t
> substituting Bohr radius equation r = 4piE0 n^{2h}^2/me^2 we get:
> acceleration = q^2/ 8 \pi^2E0 h / t [ 1/n1 ? 1/n2 ]
> In other words an equation describing an electron's acceleration,
> that is independent of wavelength or mass.Just what an equation
> describing an accelerating mass should be like in Newtonian
> gravitational theory.
> The question arises:is this a route into quantum gravity?
What does the acceleration that you calculate mean ? When the hydrogen
atom absorbs a photon of appropriate energy, the electron moves to a
higher energy level. Therefore the wavefunction of the state changes.
However, you can't understand the hydrogen atom by assuming the
electrons are particles ! That is the whole point of solving the
Schrodinger wave equation.
alistair
Apr19-04, 03:18 AM
<jabberwocky><div class="vbmenu_control"><a href="jabberwocky:;" onClick="newWindow=window.open('','usenetCode','toolbar=no, location=no,scrollbars=yes,resizable=yes,status=no ,width=650,height=400'); newWindow.document.write('<HTML><HEAD><TITLE>Usenet ASCII</TITLE></HEAD><BODY topmargin=0 leftmargin=0 BGCOLOR=#F1F1F1><table border=0 width=625><td bgcolor=midnightblue><font color=#F1F1F1>This Usenet message\'s original ASCII form: </font></td></tr><tr><td width=449><br><br><font face=courier><UL><PRE>> What does the acceleration that you calculate mean ? When the hydrogen\n> atom absorbs a photon of appropriate energy, the electron moves to a\n> higher energy level. Therefore the wavefunction of the state changes.\n> However, you can\'t understand the hydrogen atom by assuming the\n> electrons are particles ! That is the whole point of solving the\n> Schrodinger wave equation.\n\nI am saying that a particle that absorbs a graviton moves closer to\nthe mass that emitted the graviton, and that the particle accelerates\ntowards the emitting mass.This particle is made of two smaller\nparticles,one of which orbits the other.What we would call the\ngravitational acceleration of the entire particle collection is\nrelated to the change in orbital velocity of the orbiting particle.The\nchange in orbital velocity being caused by the absorption of a\ngraviton over the time it takes the entire particle collection to\naccelerate towards the emitting mass.\n\nNobody knows if an electron is a particle or a wave!!\nThe wavefunction squared is proportional to the probability of a point\nlike PARTICLE existing at a certain position in space. I am using the\nBohr model\nin the hope that it can yield insight into a proper theory of quantum\ngravity.\n\n</UL></PRE></font></td></tr></table></BODY><HTML>');"> <IMG SRC=/images/buttons/ip.gif BORDER=0 ALIGN=CENTER ALT="View this Usenet post in original ASCII form"> View this Usenet post in original ASCII form </a></div><P></jabberwocky>> What does the acceleration that you calculate mean ? When the hydrogen
> atom absorbs a photon of appropriate energy, the electron moves to a
> higher energy level. Therefore the wavefunction of the state changes.
> However, you can't understand the hydrogen atom by assuming the
> electrons are particles ! That is the whole point of solving the
> Schrodinger wave equation.
I am saying that a particle that absorbs a graviton moves closer to
the mass that emitted the graviton, and that the particle accelerates
towards the emitting mass.This particle is made of two smaller
particles,one of which orbits the other.What we would call the
gravitational acceleration of the entire particle collection is
related to the change in orbital velocity of the orbiting particle.The
change in orbital velocity being caused by the absorption of a
graviton over the time it takes the entire particle collection to
accelerate towards the emitting mass.
Nobody knows if an electron is a particle or a wave!!
The wavefunction squared is proportional to the probability of a point
like PARTICLE existing at a certain position in space. I am using the
Bohr model
in the hope that it can yield insight into a proper theory of quantum
gravity.
vBulletin® v3.7.6, Copyright ©2000-2009, Jelsoft Enterprises Ltd.