View Full Version : improper integral
ggcheck
Feb21-08, 05:52 PM
I used u substitution to get to this point:
\lim_{R\rightarrow\ 3-}} \int_{-3}^{R-3} (\frac{u + 3}{sqrt{u}}) du
is the only way to proceed from here using integration by parts?
sutupidmath
Feb21-08, 06:19 PM
I used u substitution to get to this point:
\lim_{R\rightarrow\ 3-}} \int_{-3}^{R-3} (\frac{u + 3}{sqrt{u}}) du
is the only way to proceed from here using integration by parts?
If your calculations are correct up to this point, i do not think you need to use integ by parts. Simply just try to rearrange the integrand like this
(u+3)/u^1/2= u/u^1/2 +3/u^1/2 = u^1-1/2 +3u^-1/2 and i guess you will be fine!!!!
ggcheck
Feb21-08, 06:25 PM
If your calculations are correct up to this point, i do not think you need to use integ by parts. Simply just try to rearrange the integrand like this
(u+3)/u^1/2= u/u^1/2 +3/u^1/2 = u^1-1/2 +3u^-1/2 and i guess you will be fine!!!!
ahhh, I didn't think to break up the fraction, for some reason I missed that
thanks :)
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