indigojoker
Apr23-08, 07:02 AM
I am baffled by what exactly it means to have the following (ingoing, outgoing) lepton pair configuration: (0,\nu_L e_R^+) and (e_L^- \bar{\nu}_R,0)
This specific question was asked in Halzen and Martin exercise 12.3.
How is it possible to have 0 in going particles and a neutrino and electron going out? I know that an ingoing right-handed antineutrino is the same as a out going lefthanded neutrino, etc, but just trying to grasp what exactly this (0,\nu_L e_R^+) and (e_L^- \bar{\nu}_R,0) configuration means physically is confusing.
Did Halzen and Martin specifically give this example just to show one can switching ingoing and outgoing particles without looking at its physical consequences?
This specific question was asked in Halzen and Martin exercise 12.3.
How is it possible to have 0 in going particles and a neutrino and electron going out? I know that an ingoing right-handed antineutrino is the same as a out going lefthanded neutrino, etc, but just trying to grasp what exactly this (0,\nu_L e_R^+) and (e_L^- \bar{\nu}_R,0) configuration means physically is confusing.
Did Halzen and Martin specifically give this example just to show one can switching ingoing and outgoing particles without looking at its physical consequences?