Could somebody explain to me why the degree of freedom of graviton isD(D-3)/2??

[yyoon@fas.harvard.edu]

Could somebody explain to me why the degree of freedom of graviton is
D(D-3)/2?

Thanks in advance

Youngsub

[thomas_larsson_01@hotmail.com]

On 4 Maj, 22:30, yy...@fas.harvard.edu wrote:
> Could somebody explain to me why the degree of freedom of graviton is
> D(D-3)/2?
>


The metric is a symmetric 2-tensor with D(D+1)/2 components.

Diffeomorphisms give D constraints. Since these constraints are
first class, they count twice (constraint + gauge fixing condition).

D(D+1)/2 - 2D = D(D-3)/2.