David Williams
May6-04, 07:52 AM
<jabberwocky><div class="vbmenu_control"><a href="jabberwocky:;" onClick="newWindow=window.open('','usenetCode','toolbar=no, location=no,scrollbars=yes,resizable=yes,status=no ,width=650,height=400'); newWindow.document.write('<HTML><HEAD><TITLE>Usenet ASCII</TITLE></HEAD><BODY topmargin=0 leftmargin=0 BGCOLOR=#F1F1F1><table border=0 width=625><td bgcolor=midnightblue><font color=#F1F1F1>This Usenet message\'s original ASCII form: </font></td></tr><tr><td width=449><br><br><font face=courier><UL><PRE>-> What is the magnitude of the temperature of space at 20 - 70 AU from the sun\n-> And how much would a piece of metal contract by at this temperature?\n\nWhat do you mean by "the temperature of space"?\n\nIf you mean the temperature at which a body would be in equilibrium\nwith the local radiation environment - principally sunlight, even at\nthat distance from the sun - then the (absolute) temperature will be\ninversely proportional to the square-root of the distance from the sun,\nsince the intensity of sunlight is proportional to R^-2, and the rate\nof radiation from the body is proportional to T^4. So, for example, at\n49 AU, the temperature will be 1/7 of the temperature at 1 AU. Here at\n1 AU the temperature is around 280 K, so at 49 AU it would be 40 K.\n\nWhat kind of metal?\n\ndow\n</UL></PRE></font></td></tr></table></BODY><HTML>');"> <IMG SRC=/images/buttons/ip.gif BORDER=0 ALIGN=CENTER ALT="View this Usenet post in original ASCII form"> View this Usenet post in original ASCII form </a></div><P></jabberwocky>-> What is the magnitude of the temperature of space at 20 - 70 AU from the sun
-> And how much would a piece of metal contract by at this temperature?
What do you mean by "the temperature of space"?
If you mean the temperature at which a body would be in equilibrium
with the local radiation environment - principally sunlight, even at
that distance from the sun - then the (absolute) temperature will be
inversely proportional to the square-root of the distance from the sun,
since the intensity of sunlight is proportional to R^-2, and the rate
of radiation from the body is proportional to T^4. So, for example, at
49 AU, the temperature will be 1/7 of the temperature at 1 AU. Here at
1 AU the temperature is around 280 K, so at 49 AU it would be 40 K.
What kind of metal?
dow
-> And how much would a piece of metal contract by at this temperature?
What do you mean by "the temperature of space"?
If you mean the temperature at which a body would be in equilibrium
with the local radiation environment - principally sunlight, even at
that distance from the sun - then the (absolute) temperature will be
inversely proportional to the square-root of the distance from the sun,
since the intensity of sunlight is proportional to R^-2, and the rate
of radiation from the body is proportional to T^4. So, for example, at
49 AU, the temperature will be 1/7 of the temperature at 1 AU. Here at
1 AU the temperature is around 280 K, so at 49 AU it would be 40 K.
What kind of metal?
dow