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moonlit
May8-04, 07:34 PM
I have a problem I'm working on, is the following work correct?

1) The drawing shows a rectangular block of glass (n = 1.52) surrounded by a liquid with n = 1.65. A ray of light is incident of the glass at point A with a 30.0° angle of incidence. At what angle does the ray leave the glass at point B?

sin 30 deg(1.65)=sin theta g (1.52)
sin -1[sin 30 deg(1.65)/(1.52) = theta g
= 32.87 deg

Dr Transport
May9-04, 09:45 AM
if point B is on the opposite side of the plate from point A, the angle the ray leaves is the same as it enters, 30 degrees. The only difference is that it is shifted.