swamanator
Aug21-08, 10:16 PM
ok so i am new to calculus ...actully havnt even started to learn it....to make life easier im starting before school starts .....so out of the many problems i will have in the future ...this is my first one ...
the instruction is::find the derivative of the function :: y = 3x^3 + 2x^2 + x + 5
so using f'(x)= lim h-->0 -- f(x+h)-f(x)/h
i come to:: [ 3(x+h)^3 + 2(x+h)^2 + (x+h) + 5] - [3x^3 + 2x^2 + x + 5] / h
now this is where i was stuck ....i dont want to expand all that stuff cuz that would take not forever ..but a significant amt of time ...so i wanted to ask ...are there any shortcuts to come to the expanded form?
i solved this problem using the first 4 derivitives i learned y=c, y=cx, y=cx^n and another one ...but i wanted to know how to do this algebraically
thanks
the instruction is::find the derivative of the function :: y = 3x^3 + 2x^2 + x + 5
so using f'(x)= lim h-->0 -- f(x+h)-f(x)/h
i come to:: [ 3(x+h)^3 + 2(x+h)^2 + (x+h) + 5] - [3x^3 + 2x^2 + x + 5] / h
now this is where i was stuck ....i dont want to expand all that stuff cuz that would take not forever ..but a significant amt of time ...so i wanted to ask ...are there any shortcuts to come to the expanded form?
i solved this problem using the first 4 derivitives i learned y=c, y=cx, y=cx^n and another one ...but i wanted to know how to do this algebraically
thanks