sadakaa
Sep30-08, 01:43 AM
A rope and pulley have negligible mass, and the pulley is frictionless. The coefficient of kinetic friction between the first block (8 kg) and the table is \mu=.250. The blocks are released from rest. USE THE ENERGY METHODS TO CALCULATE THE SPEED OF BLOCK 2 (6 kg) after it has descended 1.5 meters.
Basically there's a diagram: Block #1 rests on the table and is connected by a rope that goes through a pulley to block #2, which is hanging off the table.
E = K + U
W = FDcos\Theta = \DeltaE
\SigmaF = F(Tens) - F(fric)
Block #1:
E-initial = PE = (6)(9.8)(1.5)
E-final = KE = 1/2 (6) v^2
Block #2:
E-initial = PE = ?
E-final = KE = ?
F = F(tens) - (8)(9.8)(.25)
Whats the next step??
Basically there's a diagram: Block #1 rests on the table and is connected by a rope that goes through a pulley to block #2, which is hanging off the table.
E = K + U
W = FDcos\Theta = \DeltaE
\SigmaF = F(Tens) - F(fric)
Block #1:
E-initial = PE = (6)(9.8)(1.5)
E-final = KE = 1/2 (6) v^2
Block #2:
E-initial = PE = ?
E-final = KE = ?
F = F(tens) - (8)(9.8)(.25)
Whats the next step??