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If a sequence of measurable functions (real-valued) converges in measure, is it true that you can find a subsequence that converges almost uniformly? (This is obviously true if m*(domain) is finite...but in general is it?) If so, can someone outline a little why?
jostpuur
Oct10-08, 05:37 PM
Does the almost uniform convergence mean that the essential supremum of f-f_n approaches zero?
If so, I think I came up with a very simple counter example to your claim that m*(domain)<oo would be enough for this.
morphism
Oct10-08, 05:57 PM
Does the almost uniform convergence mean that the essential supremum of f-f_n approaches zero?
No, the usual definition goes something like this: f_n \to f almost uniformly if for every \epsilon > 0 there is a set E of measure less than \epsilon such that f_n \to f uniformly on the complement of E.
This is not the same as convergence in L^\infty.
What the OP is asking turns out to be true, for all measure spaces. It follows from a result that's sometimes called the "F. Riesz convergence lemma/theorem".
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