View Full Version : Gravitational field differential between dead and alive cats
azeynel1@gmail.com
Oct13-08, 05:00 AM
Lubos Motl writes that "dead and alive cats have different
gravitational fields." I wasn't sure if this was a joke. Is it?
http://motls.blogspot.com/2008/10/observables-in-quantum-gravity.html
A little bit of research shows that the gravitational field
differential between dead and alive cats originated with Lubos Motl in
his 2005 post called John Baez and quantum gravity
http://motls.blogspot.com/2005/09/john-baez-and-quantum-gravity.html :
# One can't imagine that gravity is classical; my simpler argument for
# the same statement is that the fate of the Schrodinger cat is decided
# probabilistically (via the radioactive atom), and because a dead cat
# creates a different gravitational field than an alive cat (imagine a
# planetary-size cat if you have problems to imagine a cat's gravitational
# field), the gravitational field can't evolve "classically" either: everything
# must be probabilistic if something is probabilistic.
About a year later Philip Dorrell includeded the quip in his blog post
intending "to write the shortest possible explanation of what is
really going on with Schroedinger's Cat."
http://www.1729.com/blog/SchroedingersCat.html
# No doubt there are significant electromagnetic effects =96 probably
# the cat has a slight electric charge on it's fur. (Changes in
# static electric field would travel at close to the speed of light.)
# Maybe the difference in gravitational field between a live and a
# dead cat is enough to correlate your wave function and the
# cat's wave function. (And we know that gravitational waves
# travel at the speed of light.)
In 2007 Q_Goest repeated a variation of the story in a physics forums
post on QM and gravity:
http://www.physicsforums.com/archive/index.php/t-154792.html
# But instead, let's put the box on a set of weight scales that
# will tell where the center of gravity of the entire box is and
# thus the location of the cat. If the cat is walking around the
# box, we know it's alive and thus gravity must prevent this
# cat from being in this state of dead/alive. If on the other
# hand, if the cat drops dead we might detect the cat falling
# to the floor by using these weight sensors which might
# registar a momentary decrease in weight as the cat's legs
# buckle, then increase in weight as the cat hits the floor.
# Gravity alone is all that's required to distinguish a live/dead cat.
But the question if Lubos Motl intended this as a joke is not
resolved. Leucipo commenting on the original post wasn't sure:
http://motls.blogspot.com/2008/10/observables-in-quantum-gravity.html
Lubos, you should refine a bit your SchrCat argument: charge, mass and
energy and preserved under collapse, so gravity does not feel it.
(Or was it suppossed to be a joke?)
Zeynel
science1.wordpress.com
Norm Dresner
Oct14-08, 05:00 AM
<azeynel1@gmail.com> wrote in message
news:f39fe3e8-b00a-4b3a-b7b9-c31625090d54@v28g2000hsv.googlegroups.com...
| Lubos Motl writes that "dead and alive cats have different
| gravitational fields." I wasn't sure if this was a joke. Is it?
|
| http://motls.blogspot.com/2008/10/observables-in-quantum-gravity.html
Well ... even assuming that the live cat is motionless, there's the beating
of its heart and the contractions of its diaphragm which do slightly
redistribute the total mass dynamically. I suppose if your detector is
sensitive enough, you could imagine measuring this.
Norm
Roger L Hale
Oct14-08, 05:00 AM
In article <f39fe3e8-b00a-4b3a-b7b9-c31625090d54@v28g2000hsv.googlegroups.com>,
<azeynel1@gmail.com> wrote:
>Lubos Motl writes that "dead and alive cats have different
>gravitational fields." I wasn't sure if this was a joke. Is it?
>
>http://motls.blogspot.com/2008/10/observables-in-quantum-gravity.html
>
>A little bit of research shows that the gravitational field
>differential between dead and alive cats originated with Lubos Motl in
>his 2005 post called John Baez and quantum gravity
>
>http://motls.blogspot.com/2005/09/john-baez-and-quantum-gravity.html :
>
># One can't imagine that gravity is classical; my simpler argument for
># the same statement is that the fate of the Schrodinger cat is decided
># probabilistically (via the radioactive atom), and because a dead cat
># creates a different gravitational field than an alive cat (imagine a
># planetary-size cat if you have problems to imagine a cat's gravitational
># field), the gravitational field can't evolve "classically" either: everything
># must be probabilistic if something is probabilistic.
...
>But the question if Lubos Motl intended this as a joke is not
>resolved. Leucipo commenting on the original post wasn't sure:
>
>http://motls.blogspot.com/2008/10/observables-in-quantum-gravity.html
>
>Lubos, you should refine a bit your SchrCat argument: charge, mass and
>energy [are] preserved under collapse, so gravity does not feel it.
>
>(Or was it suppossed to be a joke?)
>
>Zeynel
>science1.wordpress.com
I see no more a joke here than in Schroedinger's original Gedankenblitz.
While total charge, spin, and motion are conserved, their higher moments
are not. If, say, a nuclear winter, triggered by a Geiger count, froze the
oceans, the earth's tides (its moon-coupled quadrupole moment) would change
(diminish, I think) in height and lag, and the moon's orbit would change
(slow, I think) its expansion, a strictly gravitational effect. Likewise
even for a cat: its density-of-motion (stress) tensor T differs between
its alive and dead states, so its Einstein curvature tensor G = 8 \pi T
differs. The effects of higher moments diminish with distance as higher
powers than the square, but, classically or quantumly, are still very much
present.
The image one gets is of a superposition of two evolving configurations,
one with the moon orbiting closer, one farther, in separate 'worlds' which
feel no classical effect from each other; presumably due to their
decorrelated wave-functions. What is not clear, until one has a good
theory of quantum gravity, is perhaps how one may split the gravitational
state into configuration and wave so that this works self-consistently
and the world works the way we see.
Yours,
Roger Hale
rlh at theworld.com
azeynel1@gmail.com
Oct17-08, 05:00 AM
On Oct 13, 7:37*pm, Norm Dresner <nd...@att.net> wrote:
>
> Well ... even assuming that the live cat is motionless, there's the beating
> of its heart and the contractions of its diaphragm which do slightly
> redistribute the total mass dynamically. *I suppose if your detector is
> sensitive enough, you could imagine measuring this.
Lubos Motl kindly replied in my blog that he was serious in his claim.
So that answers my question.
I also wanted to note, if anyone is interested, that his criteria for
death is that the dead cat is closer to the ground:
# What matter is that if a cat dies - because
# of poison or the hammer, as in the normal
# Schrödinger cat setup - the head drops down,
# getting closer to the floor. A cat lying dead
# on the floor has e.g. a higher quadrupole
# moment than the alive cat, because it is
# flatter while the alive one is more spherical,
# so this can be measured not only in the
# vicinity of the box but even at infinity.
My concern with this is that it cannot differentiate between a dead
cat and a sleeping cat.
Thanks for your replies.
Rock Brentwood
Oct22-08, 05:00 AM
On Oct 12, 2:12Â*pm, azeyn...@gmail.com wrote:
> Lubos Motl writes that "dead and alive cats have different
> gravitational fields." I wasn't sure if this was a joke. Is it?
No, of course not. If you put a torsion balance next to a box
containing a geiger-activated lever, the balance will not gradually
shift from point A to point B over a long period of time, as if it
were tracking some kind of superposition-average of the two lever
states. Rather, it will shift in the small amount of time it takes for
gravity to take effect on it, after the lever inside the box has
moved.
Lubos is just reiterating a point I've raised here many times here and
in sci.physics over the past 20 years.
I think there is, lurking under all of this, an actual real live No Go
Theorem for Quantum Gravity itself -- a theorem which asserts the
fundamental impossiblity of any quantuzed theory of gravity in
spacetime dimensions of 4 or greater satisfying a set of assumptions,
each of which is widely held to (particularly the assumption that the
metric should be quantized as a fundamental field).
2004 April 6
http://groups.google.com/group/sci.physics.research/msg/e993b70fdd324bc3?hl=en&dmode=source
2003 January 11
http://groups.google.com/group/sci.physics.research/msg/5c7775dfc3147ca2?hl=en&dmode=source
2002 November 13 "Gravity Precludes Superpositions"
http://groups.google.com/group/comp.theory/msg/3eb08a9476c294fe?hl=en&dmode=source&pli=1
2002 March 3 "Many Worlds, Copenhagen, Schroedinger's Cat & Gravity"
http://groups.google.com/group/sci.physics.research/msg/e2e637ef2bf4f9c7?hl=en&dmode=source
1991 April 14 "Why Gravity Makes the Macroscopic Schroedinger's Cat
Impossible"
http://groups.google.com/group/sci.physics/msg/5ada3236d2c4c293?hl=en&dmode=source
In reply to the 1991 reply
alt.atheism (389851)
Creating Artificial Intelligence (242)
sci.physics
Recently visited [clear]
alt.astronomy
alt.bible
bionet.neuroscience
comp.dsp
comp.theory
rec.org.mensa
rec.running
sci.econ
sci.math
sci.math.research
sci.physics.foundations
sci.physics.particle
sci.physics.relativity
sci.physics.research
Groups Alerts
Create a group...
markwh04@yahoo.com | My Groups | Favorites | Profile | Help | My
Account | Sign out
sci.physics
Message from discussion Why gravity makes macroscopic Schroedinger's
cat impossible (was:
View parsed - Show only message text
Path: gmdzi!unido!fauern!ira.uka.de!sol.ctr.columbia.edu !spool.mu.edu!
uwm.edu!linac!unixhub!slacvm!doctorj
From: DOCT...@SLACVM.SLAC.STANFORD.EDU (Jon J Thaler)
Newsgroups: sci.physics
Subject: Re: Why gravity makes macroscopic Schroedinger's cat
impossible (was:
Message-ID: <91104.152939DOCTORJ@SLACVM.SLAC.STANFORD.EDU>
Date: 14 Apr 91 23:29:39 GMT
Organization: Stanford Linear Accelerator Center
Lines: 30
In article <11...@uwm.edu>, ma...@csd4.csd.uwm.edu (Mark William
Hopkins) says:
>(1) The whole graviton idea is way off base, as is shown by minor
>inconsistencies like this. Gravity's not a field. It look nothing like a
>field, it acts nothing like it. There are no gravitons. It's warped
>spacetime
>and that's all it is!
> If gravity is not subject to the rules of QM, then QM is wrong. It is easy to show (via
> a Heisenberg microscope tpye argument) that the uncertainty principle will be
> violated by the existence of *ANY* non-QM phenomenon. This has nothing to
> do with the possible breakdown of QM at the Planck length; it is [sic] strictly a long
> distance (ie, d >> planck) argument, and it applies equally well to
> variations in the geometry of spacetime.
It has everything to do with the violation of UP at macroscopic scales
vs. microscopic scales and is therefore strictly NOT a long-diistance
phenonemon.
Yes, if some degrees of freedom in a system remain classical, then
Heisenberg fails. In a way, this is already widely accepted and in
use. Any time you convert a Poisson bracket to a Dirac bracket, you're
"classicalizing" the conjugate pairs that are being filtered out by
the "Diracization" of the bracket. This is how you handle second class
constraints.
So, there's nothing threoretically mandating that everything under the
sun should be subject to the rules governing canonical quantization.
It is very well possible to have a classico-quantum theory. The
elements that reside in foundational physics (Hilbert spaces, C*-
algebras, state spaces as linear operators spaces on C*-algebras,
etc.) do not pay any mind to whether they are being used for
classical, quantum or classico-quantum hybrids. They/re above all that
fray.
Even the Lueder's "projection" or "wave function collapse" rule can be
formulated in a way that makes it entirely independent of the quantum
vs. classical distinction (that is, there is both a classical and even
a classico-quantum version of the Lueder's rule)..
The relevant question was never any of these, but rather the one
question which the theoretical literature ACTUALLY focuses on: how to
get the quantum part of a system to talk back to the classical part of
a system.
> It's fun to speculate, but there is neither evidence nor need for any [sic] new
> theory to explain how the graviton gets out of a black hole, any more than a
> new theory is required to explain how the photon gets out of an electrically
> charged black hole.
The word "new" (meaning, in this context: a revision of what's
"already known") is not applicable, since there's nothing "already
known" to be "new" of, in the first place.
There's nothing inconsistent to having, for instance, the metric
remain classical while the matter fields are quantum.
There WOULD be, if you were strictly in a Riemannian space. But you
can't be, because you have matter fields described by spinors, which
requires adding to the BACKGROUND structure of the manifold the
additional structure of a (background) orthonormal frame bundle and
(background) spinor bundle structure.
(This is a point that the Jet Bundle and Gauge Theory guru,
Sardanashvily, has raised repeated over the past 20 years -- the spin
bundle for one orthonormal frame bundle is an INEQUIVALENT state space
to that for another orthonormal frame bundle and cannot be involved in
any superpositions with one another in any quantized theory).
Of necessity, you're in a Riemann-Cartan space.
But that's also your saving grace. For, the matter fields (including
the gauge fields) actually do not directly interact with the metric or
the orthonormal frame bundle. Rather, the metric/orthonormal frame
bundle only providing the setting and conditioning atop which the wave
equation or (more generally the non-linear coupled field law) are set.
Instead, the fields interact directly only with the connection.
There is nothing in any of the above that precludes the connection
from being a fully quantized field. There would be if you were in a
Riemannian geometry with the metric remaining classical, for then the
connection (being a function of the metric) would be too. Then you'd
have all sorts of problems, say, with writing the Dirac equation for a
fully quantized curved background.
Not so, however, if the geometry is a Riemann-Cartan geometry.
The interactions would be (connection -> matter & gauge fields).
(Connection <- one of the gauge fields). (Noether current for Lorentz
symmetry -> connection).
So, the question then all boils down to the one question which,
ultimately, is the one that ties directly to the kinds of thiings you
hear Sardanashvily, Diosi' (another guru on hybrid classical-quantum
theories), or Penrose talk about. That question is this: how do you
get the (quantized) matter fields to influence the (classical) metric.
That's the "back reaction" problem. More precisely, it's the back-
reaction problem for "semi-classical gravity" since people still think
there's such a thing as a "back-reaction problem for quantized gravity
with a fully quantized metric".
The answer comes right down to this. The stress tensor, which is what
goes on the left hand side of the field law, is the Noether current
for a symmetry which is not a "gauge symmetry" at all, in the usual
sense. That symmetry is the one governed by the diffeomorphism group.
In contrast to gauge groups, which gives you "passive" transformations
(that is, transformations which leave points fixed), the
diffeomorphism group gives you "active" transformations (which move
points).
If M is the space-time manifold and Diff(M) = C^{infinity}(M, M) is
the diffeomorphism group for M, then each f in Diff(M) moves a compact
region K to another region f(K).
Consequently, under the action of f, the state space for K is shifted
to the state space for f(K), which is displaced relative to K. The two
state spaces associated with K and f(K) do not transform equivalently
into one another. There is an entanglement entropy associated with the
displacement of K to f(K).
If the metric lies in the background to a fully quantized field
theory, rather than being a quantum field itself, then one way this
may happen is that in place of a single vacuum state |0>, one has a
highly degenerate vacuum consisting of a set of states |F> associated
with a subbundle FM of the tangent bundle TM that is designated as the
orthonormal frame bundle.
In place of one coherent subspace are an infinite number of them, one
for each orthonormal frame bundle. Two state spaces that disagree on
the definition of "free fall", to use the words of Penrose, will
therefore be mutually incoherent and will not participate in coherent
superpositions.
Normally, one would expect that the vacuum expectation of the
(quantized) stress tensor T^{mu nu} associated with the fields would
be <0| T^{mu nu} |0> = 0.
However, since there is an entanglement entropy created as a result of
moving any compact region K -> f(K), then an anomalous term is created
on the right-hand side of the equation. Maybe this is where something
like the Atiyah-Singer Index theorem will come into play. The
resulting equation may then be something like the one I posited here a
while back:
<FM| T^{mu nu} |FM> = (16 pi A)/h-bar G^{mu nu}(g)
where the G^{mu nu}(g) is the Einstein tensor calculated with respect
to any metric g compatible with the bundle FM.
The partition of the state space into different vacuum sectors
generated by the respective states |FM><FM|, then, also has the effect
of implementing Sardanashvily's notion that the mere presence of
vBulletin® v3.8.7, Copyright ©2000-2012, vBulletin Solutions, Inc.