Am I setting this up properly?

[Shackleford]

Can I assume I3 = 2A since the ammeter is in series between d and c?

Also, what do I do with V in the linear equations?

http://i111.photobucket.com/albums/n149/camarolt4z28/k.jpg

[Defennder]

Your KVL loop equations look ok. You're supposed to find V. You have sufficient info in your equations to solve for it.

[Shackleford]

Your KVL loop equations look ok. You're supposed to find V. You have sufficient info in your equations to solve for it.

Well, I just used the top two equations in a matrix to find I1 and I2.

I1 + I2 = 2
7I1 + 0I2 = 5

I1= .714286
I2= 1.28571

With this, I can set V = sum of the rest of the voltage drops, correct?

[Defennder]

I didn't check your calculations, but your approach is correct.

[Shackleford]

i didn't check your calculations, but your approach is correct.

i1r1 - v1 + i3r2 - i2r3 = -v ??

[Defennder]

Sorry I missed that last line of your previous post. What do you mean by "sum of the rest of the voltage drops" ?

[Shackleford]

Sorry I missed that last line of your previous post. What do you mean by "sum of the rest of the voltage drops" ?

The voltage difference from V to V should be zero.

i1r1 - v1 + i3r2 - i2r3 = -v ??

[Defennder]

How did you get that? Your equation has to be a loop KVL equation, and it looks like there isn't any loop which contains all three currents which your current equation has. But why do you need to do that? Once you've found I2 and I3 from above, just use of the original equations to get V.