ScotchDave
Feb11-09, 03:00 PM
1. The problem statement, all variables and given/known data
The formula for cyclotronic motion in SI units was shown to be p=qeBR. Show that in units in which R is in metres but p is in GeV/c p=0.3qBR
2. Relevant equations
qe^{-}=1.6 \times 10^{-19} C I think!
L=\frac{\hbar \times c}{eV}= 1.9732705 \times 10^{-7} m I think!
B = 1 eV^{2} = 1.44 \times 10^{-3} Teslas I think!
3. The attempt at a solution
So, now I get even MORE confused and try substituting stuff in, but don't get anywhere!
p = \frac{10^{9}}{1.6 \times 10^{-19} \times 1.97x10^{-7} \times 1.44\times10^{-3}}} = 2.2 \times 10^{37}
or
p = \frac{10^{9} \times1.6 \times 10^{-19}}{ 1.97x10^{-7} \times 1.44\times10^{-3}}} = 0.56
This is clearly wrong, but I'm just getting COMPLETELY confused by all of this. Can anyone help me please?
The formula for cyclotronic motion in SI units was shown to be p=qeBR. Show that in units in which R is in metres but p is in GeV/c p=0.3qBR
2. Relevant equations
qe^{-}=1.6 \times 10^{-19} C I think!
L=\frac{\hbar \times c}{eV}= 1.9732705 \times 10^{-7} m I think!
B = 1 eV^{2} = 1.44 \times 10^{-3} Teslas I think!
3. The attempt at a solution
So, now I get even MORE confused and try substituting stuff in, but don't get anywhere!
p = \frac{10^{9}}{1.6 \times 10^{-19} \times 1.97x10^{-7} \times 1.44\times10^{-3}}} = 2.2 \times 10^{37}
or
p = \frac{10^{9} \times1.6 \times 10^{-19}}{ 1.97x10^{-7} \times 1.44\times10^{-3}}} = 0.56
This is clearly wrong, but I'm just getting COMPLETELY confused by all of this. Can anyone help me please?