username12345
Mar14-09, 01:12 AM
Simplify \frac{sinx + tanx}{cscx + cotx}
I start with \frac{sinx + tanx}{cscx + cotx} = \frac{sinx + \frac{sinx}{cosx}}{\frac{1}{sinx} + \frac{cosx}{sinx}}
At this point I am stuck, I cannot see how we then get from \frac{sinx + \frac{sinx}{cosx}}{\frac{1}{cosx} + \frac{cosx}{sinx}} = \frac{sinx cosx + sin x}{1} \times \frac{sin x}{cos x}
What happened to the \frac{1}{cos x} from the denominator? I thought that would become \frac{cos x}{1} to give (sinx + \frac{sinx}{cosx}) \times ({\frac{cosx}{1} + \frac{sin x}{cos x})
I start with \frac{sinx + tanx}{cscx + cotx} = \frac{sinx + \frac{sinx}{cosx}}{\frac{1}{sinx} + \frac{cosx}{sinx}}
At this point I am stuck, I cannot see how we then get from \frac{sinx + \frac{sinx}{cosx}}{\frac{1}{cosx} + \frac{cosx}{sinx}} = \frac{sinx cosx + sin x}{1} \times \frac{sin x}{cos x}
What happened to the \frac{1}{cos x} from the denominator? I thought that would become \frac{cos x}{1} to give (sinx + \frac{sinx}{cosx}) \times ({\frac{cosx}{1} + \frac{sin x}{cos x})