View Full Version : photon propagation
Hari Seldon
Jun11-04, 06:29 AM
<jabberwocky><div class="vbmenu_control"><a href="jabberwocky:;" onClick="newWindow=window.open('','usenetCode','toolbar=no, location=no,scrollbars=yes,resizable=yes,status=no ,width=650,height=400'); newWindow.document.write('<HTML><HEAD><TITLE>Usenet ASCII</TITLE></HEAD><BODY topmargin=0 leftmargin=0 BGCOLOR=#F1F1F1><table border=0 width=625><td bgcolor=midnightblue><font color=#F1F1F1>This Usenet message\'s original ASCII form: </font></td></tr><tr><td width=449><br><br><font face=courier><UL><PRE>\n\nHi,\n\nOk, I asked this before, in a somewhat different way and since I did\nnot get any satisfying answer I\'ll try again, with a simpler example.\nSuppose we have a source (S), emitting a photon at time t and a\ndetector (D) detecting the photon at time t\', where t\' > t. Now my\nquestion is very simple and perhaps the answer is also very simple.\nHow do you calculate the amplitude to detect the photon emitted by S\nat t at the detector D at time t\'. I can think of two ways to do so.\n\n1) Use the path integral method of quantum mechanics. This means we\nmust assume the photon is initially at time t, in some state |i,t> and\nupon detection in some state |f,t\'>. The question is, what does the\ninitial (or final) state look like. First of all, can a photon be in a\nposition eigenstate? (I ask this because I heard there were problems\nwith defining a position representation wave function). I guess the\nbest description for the initial state is some superposition of\nmomentum (and position?) states, since the particle is fairly\nlocalised and we know the momentum is only in the direction of D. So\nwhat would it look like? Then if I know this, the final state looks\nsimilar. Then are there any problems with summing over all paths\nbetween these states? Or does it work exactly as with the electon. I\nask this because I still wonder whether we can apply this quantum\nmechanical principle to the photon since the photon is necesarilly a\nrelativistic particle. Don\'t we need at least relativistic quantum\nmechanics? What changes then? Or do we actually need field theory ?\nThis brings me to option 2.\n\n2) We assume the photon is in fact a virtual photon, part of a QED\ndiagram. This amplitude for the described \'experiment\' is then given\nby the photon propagator (dressed propagator?). Or is it perhaps given\nby the whole amplitude of all the corresponding diagrams for the\nprocess of emitting a photon and absorbing a photon as given by for\nexample: >---<.\n\nAs you can see I am quite confused about this simple example. I hope\nsomeone can help me nevertheless.\n\nMany thnx,\n\nHari.\n</UL></PRE></font></td></tr></table></BODY><HTML>');"> <IMG SRC=/images/buttons/ip.gif BORDER=0 ALIGN=CENTER ALT="View this Usenet post in original ASCII form"> View this Usenet post in original ASCII form </a></div><P></jabberwocky>Hi,
Ok, I asked this before, in a somewhat different way and since I did
not get any satisfying answer I'll try again, with a simpler example.
Suppose we have a source (S), emitting a photon at time t and a
detector (D) detecting the photon at time t', where t' > t. Now my
question is very simple and perhaps the answer is also very simple.
How do you calculate the amplitude to detect the photon emitted by S
at t at the detector D at time t'. I can think of two ways to do so.
1) Use the path integral method of quantum mechanics. This means we
must assume the photon is initially at time t, in some state |i,t> and
upon detection in some state |f,t'>. The question is, what does the
initial (or final) state look like. First of all, can a photon be in a
position eigenstate? (I ask this because I heard there were problems
with defining a position representation wave function). I guess the
best description for the initial state is some superposition of
momentum (and position?) states, since the particle is fairly
localised and we know the momentum is only in the direction of D. So
what would it look like? Then if I know this, the final state looks
similar. Then are there any problems with summing over all paths
between these states? Or does it work exactly as with the electon. I
ask this because I still wonder whether we can apply this quantum
mechanical principle to the photon since the photon is necesarilly a
relativistic particle. Don't we need at least relativistic quantum
mechanics? What changes then? Or do we actually need field theory ?
This brings me to option 2.
2) We assume the photon is in fact a virtual photon, part of a QED
diagram. This amplitude for the described 'experiment' is then given
by the photon propagator (dressed propagator?). Or is it perhaps given
by the whole amplitude of all the corresponding diagrams for the
process of emitting a photon and absorbing a photon as given by for
example: >---<.
As you can see I am quite confused about this simple example. I hope
someone can help me nevertheless.
Many thnx,
Hari.
Charles Francis
Jun27-04, 05:57 PM
<jabberwocky><div class="vbmenu_control"><a href="jabberwocky:;" onClick="newWindow=window.open('','usenetCode','toolbar=no, location=no,scrollbars=yes,resizable=yes,status=no ,width=650,height=400'); newWindow.document.write('<HTML><HEAD><TITLE>Usenet ASCII</TITLE></HEAD><BODY topmargin=0 leftmargin=0 BGCOLOR=#F1F1F1><table border=0 width=625><td bgcolor=midnightblue><font color=#F1F1F1>This Usenet message\'s original ASCII form: </font></td></tr><tr><td width=449><br><br><font face=courier><UL><PRE>In message <f507ac4c.0406100752.3dab3136@posting.google.com >, Hari\nSeldon <waterballon@hotmail.com> writes\n>\n>\n>Hi,\n>\n>Ok, I asked this before, in a somewhat different way and since I did\n>not get any satisfying answer I\'ll try again, with a simpler example.\n>Suppose we have a source (S), emitting a photon at time t and a\n>detector (D) detecting the photon at time t\', where t\' > t. Now my\n>question is very simple and perhaps the answer is also very simple.\n>How do you calculate the amplitude to detect the photon emitted by S\n>at t at the detector D at time t\'. I can think of two ways to do so.\n>\n>1) Use the path integral method of quantum mechanics. This means we\n>must assume the photon is initially at time t, in some state |i,t> and\n>upon detection in some state |f,t\'>. The question is, what does the\n>initial (or final) state look like.\n\nIt can be generally written as an integral of plane wave momentum states\n\n|f> = Integral dp |p><p|f>\n\nor <x|f> = Integral dp <x|p><p|f>\n\n>First of all, can a photon be in a\n>position eigenstate?\n\nNo. A photon is always absorbed or emitted in interaction. It can be\nabsorbed or emitted from an electron in a position eigenstate, but this\nis not the same as a photon in an eigenstate of position.\n\n>(I ask this because I heard there were problems\n>with defining a position representation wave function).\n\nYes there are. The wave function of a photon generally refers to x as\nthe position of detection, that is the position of the electron.\n\n>I guess the\n>best description for the initial state is some superposition of\n>momentum (and position?) states\n\nMomentum states, as above. Position is a different basis, so you can\nalso do an FT and write it as an integral of position states\n\n|f> = Integral dp |x><x|f>\n\nbut the momentum state representation is more useful, as momentum states\ndo not change in time, so it gives you the time evolution of the photon\nstate.\n\n>, since the particle is fairly\n>localised and we know the momentum is only in the direction of D. So\n>what would it look like? Then if I know this, the final state looks\n>similar. Then are there any problems with summing over all paths\n>between these states? Or does it work exactly as with the electon.\n\nIt works the same way.\n\n>I\n>ask this because I still wonder whether we can apply this quantum\n>mechanical principle to the photon since the photon is necesarilly a\n>relativistic particle. Don\'t we need at least relativistic quantum\n>mechanics? What changes then? Or do we actually need field theory ?\n\nWe do need relativistic quantum mechanics, which leads into needing\nfield theory.\n\n>This brings me to option 2.\n>\n>2) We assume the photon is in fact a virtual photon, part of a QED\n>diagram. This amplitude for the described \'experiment\' is then given\n>by the photon propagator (dressed propagator?). Or is it perhaps given\n>by the whole amplitude of all the corresponding diagrams for the\n>process of emitting a photon and absorbing a photon as given by for\n>example: >---<.\n\nYes.\n\n--\nCharles Francis\n\n</UL></PRE></font></td></tr></table></BODY><HTML>');"> <IMG SRC=/images/buttons/ip.gif BORDER=0 ALIGN=CENTER ALT="View this Usenet post in original ASCII form"> View this Usenet post in original ASCII form </a></div><P></jabberwocky>In message <f507ac4c.0406100752.3dab3136@posting.google.com>, Hari
Seldon <waterballon@hotmail.com> writes
>
>
>Hi,
>
>Ok, I asked this before, in a somewhat different way and since I did
>not get any satisfying answer I'll try again, with a simpler example.
>Suppose we have a source (S), emitting a photon at time t and a
>detector (D) detecting the photon at time t', where t' > t. Now my
>question is very simple and perhaps the answer is also very simple.
>How do you calculate the amplitude to detect the photon emitted by S
>at t at the detector D at time t'. I can think of two ways to do so.
>
>1) Use the path integral method of quantum mechanics. This means we
>must assume the photon is initially at time t, in some state |i,t> and
>upon detection in some state |f,t'>. The question is, what does the
>initial (or final) state look like.
It can be generally written as an integral of plane wave momentum states
|f> =[/itex] Integral dp |p><p|f>
or <x|f> = Integral dp <x|p><p|f>
>First of all, can a photon be in a
>position eigenstate?
No. A photon is always absorbed or emitted in interaction. It can be
absorbed or emitted from an electron in a position eigenstate, but this
is not the same as a photon in an eigenstate of position.
>(I ask this because I heard there were problems
>with defining a position representation wave function).
Yes there are. The wave function of a photon generally refers to x as
the position of detection, that is the position of the electron.
>I guess the
>best description for the initial state is some superposition of
>momentum (and position?) states
Momentum states, as above. Position is a different basis, so you can
also do an FT and write it as an integral of position states
|f> = Integral [itex]dp |x><x|f>
but the momentum state representation is more useful, as momentum states
do not change in time, so it gives you the time evolution of the photon
state.
>, since the particle is fairly
>localised and we know the momentum is only in the direction of D. So
>what would it look like? Then if I know this, the final state looks
>similar. Then are there any problems with summing over all paths
>between these states? Or does it work exactly as with the electon.
It works the same way.
>I
>ask this because I still wonder whether we can apply this quantum
>mechanical principle to the photon since the photon is necesarilly a
>relativistic particle. Don't we need at least relativistic quantum
>mechanics? What changes then? Or do we actually need field theory ?
We do need relativistic quantum mechanics, which leads into needing
field theory.
>This brings me to option 2.
>
>2) We assume the photon is in fact a virtual photon, part of a QED
>diagram. This amplitude for the described 'experiment' is then given
>by the photon propagator (dressed propagator?). Or is it perhaps given
>by the whole amplitude of all the corresponding diagrams for the
>process of emitting a photon and absorbing a photon as given by for
>example: >---<.
Yes.
--
Charles Francis
p.kinsler@imperial.ac.uk
Jun30-04, 05:38 PM
<jabberwocky><div class="vbmenu_control"><a href="jabberwocky:;" onClick="newWindow=window.open('','usenetCode','toolbar=no, location=no,scrollbars=yes,resizable=yes,status=no ,width=650,height=400'); newWindow.document.write('<HTML><HEAD><TITLE>Usenet ASCII</TITLE></HEAD><BODY topmargin=0 leftmargin=0 BGCOLOR=#F1F1F1><table border=0 width=625><td bgcolor=midnightblue><font color=#F1F1F1>This Usenet message\'s original ASCII form: </font></td></tr><tr><td width=449><br><br><font face=courier><UL><PRE>Hari Seldon <waterballon@hotmail.com> wrote:\n> Ok, I asked this before, in a somewhat different way and since I did\n> not get any satisfying answer I\'ll try again, with a simpler example.\n> Suppose we have a source (S), emitting a photon at time t and a\n> detector (D) detecting the photon at time t\', where t\' > t. Now my\n> question is very simple and perhaps the answer is also very simple.\n> How do you calculate the amplitude to detect the photon emitted by S\n> at t at the detector D at time t\'.\n\nFirst I would ask myself "what shape are the photons that the\nsource emits?" This is of course a ghastly, vague question full\nof misconceptions, but it starts us off.\n\nPerhaps the source emits light equally in all directions, in\nspherical waves. If so, I would make my photons using a basis\nof spherically symmetric solutions to Maxwells equations.\nEach photon is then a single excitation of a quantised simple\nharmonic oscillator living inside one of the basis functions\n(or "mode").\n\nBut maybe my source isn\'t monochromatic, but my basis functions\nare. Maybe the emitted light has unexpected statitics or\ncorrelations. This means I have to build my emitted light out\nof some suitable combination of modes containing convenient\nquantum states.\n\nNow I\'ve built a description of the light emitted by my source,\nI have to propagate the light through space -- in a vacuum this\nwould hopefuly be trivial, but if in some kind of nonlinear\nwaveguide it would likely be hard. Lets just assume I can do\nit.\n\nNow I\'ve propagated the light emitted from my source, I can see\nhow it overlaps with my detector. This is all very well, but\nsuddenly I realise I don\'t know how my detector works! So I\nbuild a model ... maybe it\'s something as simple as a two-level\natom.\n\nSo now the propagated light overlaps with the detector, and they\ninteract by (e.g.) a simple dipole interaction. The field-detector\nsystem moves into a superposition of |field,unexcited-atom>\nand |field-less-one-photon,excited-atom>, and the amount of\nsuperposition will change with time (in simple cases it might\noscillate).\n\nSimplistically, I could now assume that the probability that\na photon has been detected is equal to the probability that\nthe atom is excited. Most people would want to add in some\nsort of collapse or decoherence process first though :-).\n\n--\n---------------------------------+---------------------------------\nDr. Paul Kinsler\nBlackett Laboratory (QOLS) (ph) +44-20-759-47520 (fax) 47714\nImperial College London, Dr.Paul.Kinsler@physics.org\nSW7 2BW, United Kingdom. http://www.qols.ph.ic.ac.uk/~kinsle/\n\n</UL></PRE></font></td></tr></table></BODY><HTML>');"> <IMG SRC=/images/buttons/ip.gif BORDER=0 ALIGN=CENTER ALT="View this Usenet post in original ASCII form"> View this Usenet post in original ASCII form </a></div><P></jabberwocky>Hari Seldon <waterballon@hotmail.com> wrote:
> Ok, I asked this before, in a somewhat different way and since I did
> not get any satisfying answer I'll try again, with a simpler example.
> Suppose we have a source (S), emitting a photon at time t and a
> detector (D) detecting the photon at time t', where t' > t. Now my
> question is very simple and perhaps the answer is also very simple.
> How do you calculate the amplitude to detect the photon emitted by S
> at t at the detector D at time t'.
First I would ask myself "what shape are the photons that the
source emits?" This is of course a ghastly, vague question full
of misconceptions, but it starts us off.
Perhaps the source emits light equally in all directions, in
spherical waves. If so, I would make my photons using a basis
of spherically symmetric solutions to Maxwells equations.
Each photon is then a single excitation of a quantised simple
harmonic oscillator living inside one of the basis functions
(or "mode").
But maybe my source isn't monochromatic, but my basis functions
are. Maybe the emitted light has unexpected statitics or
correlations. This means I have to build my emitted light out
of some suitable combination of modes containing convenient
quantum states.
Now I've built a description of the light emitted by my source,
I have to propagate the light through space -- in a vacuum this
would hopefuly be trivial, but if in some kind of nonlinear
waveguide it would likely be hard. Lets just assume I can do
it.
Now I've propagated the light emitted from my source, I can see
how it overlaps with my detector. This is all very well, but
suddenly I realise I don't know how my detector works! So I
build a model ... maybe it's something as simple as a two-level
atom.
So now the propagated light overlaps with the detector, and they
interact by (e.g.) a simple dipole interaction. The field-detector
system moves into a superposition of |field,unexcited-atom>
and |field-less-one-photon,excited-atom>, and the amount of
superposition will change with time (in simple cases it might
oscillate).
Simplistically, I could now assume that the probability that
a photon has been detected is equal to the probability that
the atom is excited. Most people would want to add in some
sort of collapse or decoherence process first though :-).
--
---------------------------------+---------------------------------
Dr. Paul Kinsler
Blackett Laboratory (QOLS) (ph) +44-20-759-47520 (fax) 47714
Imperial College London, Dr.Paul.Kinsler@physics.org
SW7 2BW, United Kingdom. http://www.qols.ph.ic.ac.uk/~kinsle/
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