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latentcorpse
Apr16-09, 06:36 PM
http://img11.imageshack.us/img11/2159/58201426.th.png (http://img11.imageshack.us/my.php?image=58201426.png)

Hi. I'm working on the attached quesiton and have got to the very last part. I've established that the tangential component of the electric field is continuous over the surface of the conductor. On the inside of the conductor, the field is 0 and so it must also be 0 outside.

We are told the field outside is a superposition of two fields:
a unifrom field E_0 and the field of a dipole.
so all we need to do is find the net field and show its' tangential component is 0.

the components of the dipole field were found in the earlier part of the question. The tangential component of the dipole field is E_\theta (as the normal is in the radial direction) and this is given by (after substitution for p)
E_\theta=\frac{a^3}{r^3} \sin{\theta} E_0

so i need to add this to the tangetnial component of the other field and make it 0.

but the other field is uniform - does that meant its' tangential component is just E_0, if so how do we get the whole thing to be 0???