drosales
Apr22-09, 08:09 PM
1. The problem statement, all variables and given/known data
For a controls class, I am to develop a simulation using AdamsView of a pendulum attached to a link arm and driven by a motor.
The pendulum must start from rest and eventually be balanced at the top of the link arm.
I am stuck at deriving the equations of motion right now. We are to use Langrangian for developing the equations.
2. Relevant equations
These are the energy equations for the system
The kinetic energy of the entire device is:
K=1/2IdO'[t]2+1/4(2(2Il+L2m)B'[t]2+4Lmr cos]B'[t]O'[t]+(2Il+L2m+2mr2-(2Il+L2m)cos[2[B[t]])O'[t]2)
The potential energy is:
P=gLm cos[B[t]]
The work of the motor is:
W=TO[t]
Paramaters(meters, kilograms, seconds)
Centroidal moment of inertia of the inverted link Il=0.0000343
Centroidal moment of inertia of the driver link Id=0.000687
Distance from the driver axis to the hinge of the inverted link, r=0.1079
Distance from the end to the centroid of the inverted link, L=0.16
Mass of the driving bar (the horizontal one), m=0.127
Mass of the inverted link, md=0.0249
O=theta
B=beta
I've attached a diagram of this.
[b]3. The attempt at a solution
Now will deriving with respect to thetas give the equation of motion for the driving link and then with respect to my betas I will get the equation for the inverted link?
I am also not sure what part the work of the motor plays in this. After deriving the equations, will they both be set equal to the work of the motor?
Any help would be greatly appreciated. Thanks
For a controls class, I am to develop a simulation using AdamsView of a pendulum attached to a link arm and driven by a motor.
The pendulum must start from rest and eventually be balanced at the top of the link arm.
I am stuck at deriving the equations of motion right now. We are to use Langrangian for developing the equations.
2. Relevant equations
These are the energy equations for the system
The kinetic energy of the entire device is:
K=1/2IdO'[t]2+1/4(2(2Il+L2m)B'[t]2+4Lmr cos]B'[t]O'[t]+(2Il+L2m+2mr2-(2Il+L2m)cos[2[B[t]])O'[t]2)
The potential energy is:
P=gLm cos[B[t]]
The work of the motor is:
W=TO[t]
Paramaters(meters, kilograms, seconds)
Centroidal moment of inertia of the inverted link Il=0.0000343
Centroidal moment of inertia of the driver link Id=0.000687
Distance from the driver axis to the hinge of the inverted link, r=0.1079
Distance from the end to the centroid of the inverted link, L=0.16
Mass of the driving bar (the horizontal one), m=0.127
Mass of the inverted link, md=0.0249
O=theta
B=beta
I've attached a diagram of this.
[b]3. The attempt at a solution
Now will deriving with respect to thetas give the equation of motion for the driving link and then with respect to my betas I will get the equation for the inverted link?
I am also not sure what part the work of the motor plays in this. After deriving the equations, will they both be set equal to the work of the motor?
Any help would be greatly appreciated. Thanks