zetafunction
May24-09, 04:49 PM
the question is, i wish to calculate the sum
\sum_{ n=1}^{N}a(n) for big N
then you can introduce a so called smoothed sum \sum_{ n=1}^{\infty}a(n)\phi (n/N)
the idea is that phi is an smoothed function that tends to zero very fast when n > N so the infinite sum is almost equal to the finite one, the question is how can i calculate this smoothed sums ??
\sum_{ n=1}^{N}a(n) for big N
then you can introduce a so called smoothed sum \sum_{ n=1}^{\infty}a(n)\phi (n/N)
the idea is that phi is an smoothed function that tends to zero very fast when n > N so the infinite sum is almost equal to the finite one, the question is how can i calculate this smoothed sums ??