View Full Version : Set element of itself
ronaldor9
May29-09, 10:36 PM
Can a set A be an element of A, or can A be not an element of A? And what would such mean in plain-speak?
Dragonfall
May29-09, 11:28 PM
Yes, if you assume it to be an axiom. See http://en.wikipedia.org/wiki/Non-well-founded_set
If you don't assume it or its negation, you cannot prove this either way.
ronaldor9
May30-09, 12:58 AM
thanks! By the way, why is it that {x: x=x} and {x: x not an element of x} do not constitute a set? The latter I would think would constitute the null set, but apparently this is wrong.
CRGreathouse
May30-09, 01:32 AM
thanks! By the way, why is it that {x: x=x} and {x: x not an element of x} do not constitute a set? The latter I would think would constitute the null set, but apparently this is wrong.
{x: x = x} is a proper class.
I would have thought that, with the Axiom of Foundation, {x: x is not an element of x} would be the empty set. (Without it might be too big to be a set, and can't be proven to be empty.)
Dragonfall
May30-09, 02:42 AM
With foundation, {x:x is not an element of x} is the proper class V. In naive set theory it forms the Russel paradox (http://en.wikipedia.org/wiki/Russell_paradox).
CRGreathouse
May30-09, 07:09 PM
Oops, I flipped that one mentally to "{x: x is an element of x}" which is the empty set with Foundation.
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