mnb96
Jul3-09, 09:38 AM
Hi!
Let's consider discrete finite signal as simple vectors x in \mathcal{R}^n. Taking the DFT (Discrete Fourier Transform) of x we obtain another vector in \mathcal{R}^n.
Is it possible to give (non-trivial) conditions under which the DFT(x) is never zero?
Let's consider discrete finite signal as simple vectors x in \mathcal{R}^n. Taking the DFT (Discrete Fourier Transform) of x we obtain another vector in \mathcal{R}^n.
Is it possible to give (non-trivial) conditions under which the DFT(x) is never zero?