View Full Version : Calculus 3... extrema
chunkyman343
Jul23-09, 11:48 PM
I have to find the extrema for the following function:
x^3+3xy+y^3
this is what i have:
fx(x,y)=3x^2+3y
fy(x,y)=3x+3y^2
then im lost on what to do next find fx(0) &fy(0) or find a determinant
maverick_starstrider
Jul23-09, 11:52 PM
Um... This section is for discussions of learning materials (i.e. textbooks and stuff) not homework problems. I'm sure a mod will move it soon. Anyways, consider that, just as in single varibale calculus, When the GRADIENT of a function is zero, you have a critical point (just like when the derivative is zero in single variable).
chunkyman343
Jul23-09, 11:58 PM
oops srry about that
maverick_starstrider
Jul24-09, 12:12 AM
That's fine. Are you making any headway with the problem?
chunkyman343
Jul24-09, 12:30 AM
i think i figured it out.... i have a relative max at (-1,-1,1)
vBulletin® v3.7.6, Copyright ©2000-2009, Jelsoft Enterprises Ltd.