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vernonner3voltazim
Jun27-04, 06:01 PM
<jabberwocky><div class="vbmenu_control"><a href="jabberwocky:;" onClick="newWindow=window.open('','usenetCode','toolbar=no, location=no,scrollbars=yes,resizable=yes,status=no ,width=650,height=400'); newWindow.document.write('<HTML><HEAD><TITLE>Usenet ASCII</TITLE></HEAD><BODY topmargin=0 leftmargin=0 BGCOLOR=#F1F1F1><table border=0 width=625><td bgcolor=midnightblue><font color=#F1F1F1>This Usenet message\'s original ASCII form: </font></td></tr><tr><td width=449><br><br><font face=courier><UL><PRE>I started a thread in sci.physics.relativity,\nbut nobody who participated could come up\nwith an answer. Here\'s a link to the most\nrecent message there:\nhttp://groups.google.com/groups?hl=en&lr=&ie=UTF-8&selm=p94Cc.41%24iU6.6%40fed1read03&rnum=15\nIn spite of the &lt;snip&gt;s, I\'m pretty sure that a\ngood-enough description of the Question can be found there.\n\nCan someone here deal with it?\n(dealing with it over there is fine)\n\nThanks!\nVernon Nemitz\n\n</UL></PRE></font></td></tr></table></BODY><HTML>');"> <IMG SRC=/images/buttons/ip.gif BORDER=0 ALIGN=CENTER ALT="View this Usenet post in original ASCII form">&nbsp;&nbsp;View this Usenet post in original ASCII form </a></div><P></jabberwocky>I started a thread in sci.physics.relativity,
but nobody who participated could come up
with an answer. Here's a link to the most
recent message there:
http://groups.google.com/groups?hl=en&lr=&ie=UTF-8&selm=p94Cc.41%24iU6.6%40fed1read03&rnum=15
In spite of the <snip>s, I'm pretty sure that a
good-enough description of the Question can be found there.

Can someone here deal with it?
(dealing with it over there is fine)

Thanks!
Vernon Nemitz

chronon
Jun30-04, 05:35 PM
<jabberwocky><div class="vbmenu_control"><a href="jabberwocky:;" onClick="newWindow=window.open('','usenetCode','toolbar=no, location=no,scrollbars=yes,resizable=yes,status=no ,width=650,height=400'); newWindow.document.write('<HTML><HEAD><TITLE>Usenet ASCII</TITLE></HEAD><BODY topmargin=0 leftmargin=0 BGCOLOR=#F1F1F1><table border=0 width=625><td bgcolor=midnightblue><font color=#F1F1F1>This Usenet message\'s original ASCII form: </font></td></tr><tr><td width=449><br><br><font face=courier><UL><PRE>vnemitz@pinn.net (vernonner3voltazim) wrote in message news:&lt;42336979.0406230842.d5fd93b@posting.google.c om&gt;...\n&gt; I started a thread in sci.physics.relativity,\n&gt; but nobody who participated could come up\n&gt; with an answer. Here\'s a link to the most\n&gt; recent message there:\n&gt; http://groups.google.com/groups?hl=en&lr=&ie=UTF-8&selm=p94Cc.41%24iU6.6%40fed1read03&rnum=15\n&gt; Can someone here deal with it?\n\nYou ask why vacuum self-energy gives a repuslion rather than a\ngravitational attraction. My understanding of this is as follows: If\nthe vacuum has energy then you need supply that energy to create more\nvacuum. Think of a piston in a sealed container – you have to do work\nto pull it out. In that case it\'s the external air pressure pushing,\nbut you should imagine a case where the work has to be done simply to\ncreate more vacuum. This means that there is effectively a negative\npressure in a vacuum with self-energy.\n\nNow Einstein\'s equations for general relativity have a pressure\ndependent term. Normally we only have positive pressures, so this\nsimply increases the effect due to matter. In this case however it\nmeans a repulsive effect. This is what powered inflation, and is why\ndark energy leads to the acceleration of the expansion of the universe\n\nYoo\'ll find a fuller explanation in Alan guth\'s book \'The Inflationary\nUniverse\'\n\nStephen Lee\nwww.chronon.org\n\n</UL></PRE></font></td></tr></table></BODY><HTML>');"> <IMG SRC=/images/buttons/ip.gif BORDER=0 ALIGN=CENTER ALT="View this Usenet post in original ASCII form">&nbsp;&nbsp;View this Usenet post in original ASCII form </a></div><P></jabberwocky>vnemitz@pinn.net (vernonner3voltazim) wrote in message news:<42336979.0406230842.d5fd93b@posting.google.com>...
> I started a thread in sci.physics.relativity,
> but nobody who participated could come up
> with an answer. Here's a link to the most
> recent message there:
> http://groups.google.com/groups?hl=en&lr=&ie=UTF-8&selm=p94Cc.41%24iU6.6%40fed1read03&rnum=15
> Can someone here deal with it?

You ask why vacuum self-energy gives a repuslion rather than a
gravitational attraction. My understanding of this is as follows: If
the vacuum has energy then you need supply that energy to create more
vacuum. Think of a piston in a sealed container – you have to do work
to pull it out. In that case it's the external air pressure pushing,
but you should imagine a case where the work has to be done simply to
create more vacuum. This means that there is effectively a negative
pressure in a vacuum with self-energy.

Now Einstein's equations for general relativity have a pressure
dependent term. Normally we only have positive pressures, so this
simply increases the effect due to matter. In this case however it
means a repulsive effect. This is what powered inflation, and is why
dark energy leads to the acceleration of the expansion of the universe

Yoo'll find a fuller explanation in Alan guth's book 'The Inflationary
Universe'

Stephen Lee
www.chronon.org

Robert Clark
Jul4-04, 07:40 AM
<jabberwocky><div class="vbmenu_control"><a href="jabberwocky:;" onClick="newWindow=window.open('','usenetCode','toolbar=no, location=no,scrollbars=yes,resizable=yes,status=no ,width=650,height=400'); newWindow.document.write('<HTML><HEAD><TITLE>Usenet ASCII</TITLE></HEAD><BODY topmargin=0 leftmargin=0 BGCOLOR=#F1F1F1><table border=0 width=625><td bgcolor=midnightblue><font color=#F1F1F1>This Usenet message\'s original ASCII form: </font></td></tr><tr><td width=449><br><br><font face=courier><UL><PRE>\nstephen@chronon.org (chronon) wrote in message news:&lt;60b2eda6.0406272237.22f72f93@posting.google. com&gt;...\n&gt; vnemitz@pinn.net (vernonner3voltazim) wrote in message news:&lt;42336979.0406230842.d5fd93b@posting.google.c om&gt;...\n&gt; &gt; I started a thread in sci.physics.relativity,\n&gt; &gt; but nobody who participated could come up\n&gt; &gt; with an answer. Here\'s a link to the most\n&gt; &gt; recent message there:\n&gt; &gt; http://groups.google.com/groups?hl=en&lr=&ie=UTF-8&selm=p94Cc.41%24iU6.6%40fed1read03&rnum=15\n&gt; &gt; Can someone here deal with it?\n&gt;\n&gt; You ask why vacuum self-energy gives a repuslion rather than a\n&gt; gravitational attraction. My understanding of this is as follows: If\n&gt; the vacuum has energy then you need supply that energy to create more\n&gt; vacuum. Think of a piston in a sealed container ? you have to do work\n&gt; to pull it out. In that case it\'s the external air pressure pushing,\n&gt; but you should imagine a case where the work has to be done simply to\n&gt; create more vacuum. This means that there is effectively a negative\n&gt; pressure in a vacuum with self-energy.\n&gt;\n&gt; ...\n\nI have a related question that I posed once to sci.physics:\n\n================================== ===================================\nFrom: Robert Clark (rclark@op.net)\nSubject: Questions on Negative energy properties Newsgroups:\nalt.sci.physics.new-theories, sci.physics\nDate: 1997/10/02\n\nI had some questions on the same theme. In regards to the quantum\nvacuum, aka zero-point energy, is this regarded as being negative\nenergy simply because the classical vacuum itself is considered to\nhave zero energy so anything "below" that must have negative energy?\nThe \'virtual\' particles of vacuum fluctuations are regarded to exist\nonly for extremely short times. Is this the only physical difference\nbetween them and \'actual\' particles? If it is, then wouldn\'t this\ndepend on the frame of reference? In a strong grav. field, time will\nappear to run slow compared to our (approximate) inertial frame. So\nparticles that were virtual in the strong grav. field would appear to\nus to be real particles and we could observe them. This seems to be\nimplied by both the phenomena of Hawking radiation and the Unruh\neffect. In Hawking radiation, a black hole will appear to radiate\nbecause virtual particles close to the event horizon can escape out of\nthe vicinity of the black hole. In the Unruh effect an accelerated\nmirror will appear to radiate due to the virtual particles it\nencounters, and time for an accelerated frame is also regarded as\nslowed compared to ours.\nHowever, this implies that whether or not you regard particles as\nreal or virtual depends on your frame. This creates problems for\ngeneral relativity, because to compute the gravitational field within\na region we need to include all the mass-energy in the region. So for\nus, we would include these \'virtual\' particles because to us they are\nactual. But in the strong grav. field the particles are virtual and\nare not observed; so the calculation of the grav. field for the region\nwould be less.\nThis assumes that the only difference in \'virtual\' particles is their\nextremely short time frames. So are there other physical differences?\nOne possibility is the fact that they are assumed to be created in\nonly particle-antiparticle pairs.\nThen a way out of the problem with GR would be if the particle\ncreated positive gravity and the antiparticle created negative\ngravity. So in both frames the result would be no net contribution. Of\ncourse, the idea that antimatter creates negative gravity is not the\nstandard view. However, the gravitational effects of antimatter have\nnot been precisely measured so this question is still open. There are\nexperiments in the works to test this using antihydrogen so this\nshould be resolved in the next few years. See the Physics FAQ, "Does\nAntimatter Fall Up or Down,"\nhttp://wwwhpcc.astro.washington.edu/mirrors/physicsfaq/grav_antimatter.html.\nAnother possible resolution would be that we should always include\nthe virtual energy in a region to compute its gravitational field.\nThis would result in a marked increase for the calculated grav. field\nso I don\'t know if this is a workable solution.\n\n\nBob Clark\n\nNote: I checked the Physics FAQ article, "Below Absolute Zero - What\nDoes Negative Temperature Mean?", and found that the question of\nnegative temperature is a separate one from that of negative energy.\nSo I changed the subject line of the post.\n\nPsychogamer64 &lt;psychogamer@juno.com&gt; wrote in article\n&lt;e6gfoqtz8GA.225@upnetnews03&gt;...\n&gt; I have found a reason why negative energy wouldn\'t exist, or how you can\ndrop temperatures below 0K. I have studied physics books. Heat IS\nenergy.\n&gt; The more energy something has, the more heat it usually has. Only at 0K in\n&gt; which anything is totally devoid of energy. To have negative energy, one has\n&gt; to cool something below absolute zero. This is a physics impossibility (even\n&gt; though in the future, someone could succeed at this) as we all know it.\n&gt; Finding negative energy or below 0K temperatures will pave the way for\n&gt; whole new physics.\n&gt; Psychogamer64\n=================================== ==================================\n\n\nThis also has relevance to the question of the possibility of\nworm-holes or warp-fields. Producing these has been called impractical\nbecause of the large amount of negative energy required. But if the\ninterpretation of what is "negative energy" is frame dependent, how\ncan it be said that large amounts can not be produced?\n\n\n\nBob Clark\n</UL></PRE></font></td></tr></table></BODY><HTML>');"> <IMG SRC=/images/buttons/ip.gif BORDER=0 ALIGN=CENTER ALT="View this Usenet post in original ASCII form">&nbsp;&nbsp;View this Usenet post in original ASCII form </a></div><P></jabberwocky>stephen@chronon.org (chronon) wrote in message news:<60b2eda6.0406272237.22f72f93@posting.google.com>...
> vnemitz@pinn.net (vernonner3voltazim) wrote in message news:<42336979.0406230842.d5fd93b@posting.google.com>...
> > I started a thread in sci.physics.relativity,
> > but nobody who participated could come up
> > with an answer. Here's a link to the most
> > recent message there:
> > http://groups.google.com/groups?hl=en&lr=&ie=UTF-8&selm=p94Cc.41%24iU6.6%40fed1read03&rnum=15
> > Can someone here deal with it?
>
> You ask why vacuum self-energy gives a repuslion rather than a
> gravitational attraction. My understanding of this is as follows: If
> the vacuum has energy then you need supply that energy to create more
> vacuum. Think of a piston in a sealed container ? you have to do work
> to pull it out. In that case it's the external air pressure pushing,
> but you should imagine a case where the work has to be done simply to
> create more vacuum. This means that there is effectively a negative
> pressure in a vacuum with self-energy.
>
> ...

I have a related question that I posed once to sci.physics:

================================================== ===================
From: Robert Clark (rclark@op.net)
Subject: Questions on Negative energy properties Newsgroups:
alt.sci.physics.new-theories, sci.physics
Date: 1997/10/02

I had some questions on the same theme. In regards to the quantum
vacuum, aka zero-point energy, is this regarded as being negative
energy simply because the classical vacuum itself is considered to
have zero energy so anything "below" that must have negative energy?
The 'virtual' particles of vacuum fluctuations are regarded to exist
only for extremely short times. Is this the only physical difference
between them and 'actual' particles? If it is, then wouldn't this
depend on the frame of reference? In a strong grav. field, time will
appear to run slow compared to our (approximate) inertial frame. So
particles that were virtual in the strong grav. field would appear to
us to be real particles and we could observe them. This seems to be
implied by both the phenomena of Hawking radiation and the Unruh
effect. In Hawking radiation, a black hole will appear to radiate
because virtual particles close to the event horizon can escape out of
the vicinity of the black hole. In the Unruh effect an accelerated
mirror will appear to radiate due to the virtual particles it
encounters, and time for an accelerated frame is also regarded as
slowed compared to ours.
However, this implies that whether or not you regard particles as
real or virtual depends on your frame. This creates problems for
general relativity, because to compute the gravitational field within
a region we need to include all the mass-energy in the region. So for
us, we would include these 'virtual' particles because to us they are
actual. But in the strong grav. field the particles are virtual and
are not observed; so the calculation of the grav. field for the region
would be less.
This assumes that the only difference in 'virtual' particles is their
extremely short time frames. So are there other physical differences?
One possibility is the fact that they are assumed to be created in
only particle-antiparticle pairs.
Then a way out of the problem with GR would be if the particle
created positive gravity and the antiparticle created negative
gravity. So in both frames the result would be no net contribution. Of
course, the idea that antimatter creates negative gravity is not the
standard view. However, the gravitational effects of antimatter have
not been precisely measured so this question is still open. There are
experiments in the works to test this using antihydrogen so this
should be resolved in the next few years. See the Physics FAQ, "Does
Antimatter Fall Up or Down,"
http://wwwhpcc.astro.washington.edu/mirrors/physicsfaq/grav_antimatter.html.
Another possible resolution would be that we should always include
the virtual energy in a region to compute its gravitational field.
This would result in a marked increase for the calculated grav. field
so I don't know if this is a workable solution.


Bob Clark

Note: I checked the Physics FAQ article, "Below Absolute Zero - What
Does Negative Temperature Mean?", and found that the question of
negative temperature is a separate one from that of negative energy.
So I changed the subject line of the post.

Psychogamer64 <psychogamer@juno.com> wrote in article
<e6gfoqtz8GA.225@upnetnews03>...
> I have found a reason why negative energy wouldn't exist, or how you can
drop temperatures below 0K. I have studied physics books. Heat IS
energy.
> The more energy something has, the more heat it usually has. Only at 0K in
> which anything is totally devoid of energy. To have negative energy, one has
> to cool something below absolute zero. This is a physics impossibility (even
> though in the future, someone could succeed at this) as we all know it.
> Finding negative energy or below 0K temperatures will pave the way for
> whole new physics.
> Psychogamer64
================================================== ===================


This also has relevance to the question of the possibility of
worm-holes or warp-fields. Producing these has been called impractical
because of the large amount of negative energy required. But if the
interpretation of what is "negative energy" is frame dependent, how
can it be said that large amounts can not be produced?



Bob Clark

vernonner3voltazim
Aug4-04, 01:23 AM
<jabberwocky><div class="vbmenu_control"><a href="jabberwocky:;" onClick="newWindow=window.open('','usenetCode','toolbar=no, location=no,scrollbars=yes,resizable=yes,status=no ,width=650,height=400'); newWindow.document.write('<HTML><HEAD><TITLE>Usenet ASCII</TITLE></HEAD><BODY topmargin=0 leftmargin=0 BGCOLOR=#F1F1F1><table border=0 width=625><td bgcolor=midnightblue><font color=#F1F1F1>This Usenet message\'s original ASCII form: </font></td></tr><tr><td width=449><br><br><font face=courier><UL><PRE>Thanks for the replies, folks!\nSorry about my delay in responding; for a few days after I\nposted my query, I never saw that it passed the moderator,\nso gave up looking. Today I found it by accident.\n\n&gt; chronon (stephen@chronon.org) wrote:\n&gt; You ask why vacuum self-energy gives a repuslion rather\n&gt; than a gravitational attraction. My understanding of\n&gt; this is as follows: If the vacuum has energy then you\n&gt; need supply that energy to create more vacuum. Think\n&gt; of a piston in a sealed container – you have to do work\n&gt; to pull it out. In that case it\'s the external air\n&gt; pressure pushing, but you should imagine a case where\n&gt; the work has to be done simply to create more vacuum.\n&gt; This means that there is effectively a negative\n&gt; pressure in a vacuum with self-energy.\n\nI do understand this, but it still does not make sense\nin the context of the Universe. The expanding Universe\nis creating more vacuum, right? The energy to do that\nshould be coming FROM that expansion. Next, if that\nnew vacuum is now a source of repulsion in the Universe,\ncausing acceleration and the creation of even more\nvacuum, then what happened to Energy Conservation?\n\nFinally, it is not clear that this "negative pressure\nproperty of the vacuum" is something that must be\nexplained in terms of virtual particles popping into\nthe vacuum. Maybe the vacuum itself ("fabric of\nspace/time") is the culprit, and the virtual\nparticles are just doing their own thing,\nindependently and blamelessly.\n\nOn the other hand, if QM and GR are ever to be\nmerged, "blameless" may not be allowed.\n\n\nrgregoryclark@yahoo.com (Robert Clark) wrote:\n&gt;\n&gt; I have a related question that I posed once to\n&gt; sci.physics:\n&gt; ================================================== =====\n&gt; Date: 1997/10/02\n&gt;\n&gt; I had some questions on the same theme. In regards\n&gt; to the quantum vacuum, aka zero-point energy, is this\n&gt; regarded as being negative energy simply because the\n&gt; classical vacuum itself is considered to have zero\n&gt; energy so anything "below" that must have negative\n&gt; energy?\n\nIt was my understanding that the zero-point energy was\npositive and not negative! GR may want it to be\nnegative per preceding text above by chronon, but\nQM never said that, so far as I know. And, in fact\nmy own Question is, IF QM SAYS THAT, THEN HOW????\n\n\n&gt; The \'virtual\' particles of vacuum fluctuations are\n&gt; regarded to exist only for extremely short times.\n&gt; Is this the only physical difference between them and\n&gt; \'actual\' particles?\n\nTo the best of my knowlegdge, that is the case. Virtual\nparticles exist on borrowed energy, but while they\nexist, they are mostly normal. One exception (not to\nexclude others) is the photon. An ordinary real photon\nalways has the same amount of energy. A virtual photon\ndoes not need to vanish when its energy drops below a\ncertain point (as would, for example, a virtual W boson)\nso its energy can be described as "decaying smoothly\nwith time" -- and the shape of this curve is identical\nto that of the simple function 1/X. This of course is\nwhy the virtual photons associated the EM Force can\ngo out to infinite range, while the Weak Force is\nextremely range-limited.\n\n&gt; If it is, then wouldn\'t this depend on the frame of\n&gt; reference? In a strong grav. field, time will appear\n&gt; to run slow compared to our (approximate) inertial\n&gt; frame. So particles that were virtual in the strong\n&gt; grav. field would appear to us to be real particles\n&gt; and we could observe them.\n\nSorry, but the rate of our perception/measurment-ability\nis identically slowed, in that grav field. So the\nvirtual particles will still remain unseen.\n\n&gt; This seems to be implied by both the phenomena of\n&gt; Hawking radiation and the Unruh effect. In Hawking\n&gt; radiation, a black hole will appear to radiate because\n&gt; virtual particles close to the event horizon can\n&gt; escape out of the vicinity of the black hole.\n\nThe hole loses mass/energy in that process, so every\nescaping virtual particle is no longer virtual.\n\n&gt; In the Unruh effect an accelerated mirror will\n&gt; appear to radiate due to the virtual particles it\n&gt; encounters, and time for an accelerated frame is\n&gt; also regarded as slowed compared to ours. However,\n&gt; this implies that whether or not you regard particles\n&gt; as real or virtual depends on your frame.\n\nIn this case any virtual particles that become real\nto an accelerating observer, will do so at the expense\nof the observer\'s energy of motion.\n\n&gt; This creates problems for general relativity,\n&gt; because to compute the gravitational field within\n&gt; a region we need to include all the mass-energy in\n&gt; the region.\n\nI\'m pretty sure that when done, this leads to the\nhistoric discrepancy ("worst embarassment in Physics")\nbetween QM and GR. 50+ orders of magnitude!\n\n&gt; So for us, we would include these \'virtual\'\n&gt; particles because to us they are actual. But in\n&gt; the strong grav. field the particles are virtual\n&gt; and are not observed; so the calculation of the\n&gt; grav. field for the region would be less.\n\nIt is the AVERAGE of their &gt;0 temporary existence\nthat leads to the discrepancy. I think.\n\n&gt; This assumes that the only difference in \'virtual\'\n&gt; particles is their extremely short time frames.\n&gt; So are there other physical differences? One\n&gt; possibility is the fact that they are assumed to\n&gt; be created in only particle-antiparticle pairs.\n&gt; Then a way out of the problem with GR would be if\n&gt; the particle created positive gravity and the\n&gt; antiparticle created negative gravity. So in\n&gt; both frames the result would be no net\n&gt; contribution. Of course, the idea that\n&gt; antimatter creates negative gravity is not the\n&gt; standard view. However, the gravitational\n&gt; effects of antimatter have not been precisely\n&gt; measured so this question is still open. There\n&gt; are experiments in the works to test this using\n&gt; antihydrogen so this should be resolved in the\n&gt; next few years. See the Physics FAQ, "Does\n&gt; Antimatter Fall Up or Down,"\n&gt; http://wwwhpcc.astro.washington.edu/mirrors/physicsfaq/grav_antimatter.html.\n\nAntimatter will fall DOWN, and the logic is:\nRemember that a gamma ray can be converted\ninto a particle/antiparticle pair. The gamma\nray consists of ordinary energy that ATTRACTS\ngravitationally. Half that gamma\'s energy\nbecomes the ordinary particle, which also\nATTRACTS gravitationally. The other half of\nthe gamma becomes the antiparticle, and the\ngravitational essence of that energy\nhas no reason to change. Electric charge\n(and some oddball aspect of the Weak Force)\nis the only difference between matter and\nantimatter particles.\n\n&gt; Another possible resolution would be that\n&gt; we should always include the virtual energy\n&gt; in a region to compute its gravitational\n&gt; field. This would result in a marked\n&gt; increase for the calculated grav. field so\n&gt; I don\'t know if this is a workable solution.\n\nNo, by 50+ orders of magnitude :)\n\n&gt; Bob Clark\n&gt;\n&gt; Note: I checked the Physics FAQ article,\n&gt; "Below Absolute Zero - What Does Negative\n&gt; Temperature Mean?", and found that the\n&gt; question of negative temperature is a\n&gt; separate one from that of negative energy.\n&gt; So I changed the subject line of the post.\n\nYeah, ordinary negative temperatures are merely\nvalues relative to some arbitrarily-specified\nzero value.\n\n&gt; Psychogamer64 &lt;psychogamer@juno.com&gt; wrote:\n&gt; &gt; I have found a reason why negative energy wouldn\'t\n&gt; &gt; exist, or how you can drop temperatures below 0K.\n&gt; &gt; I have studied physics books. Heat IS energy.\n&gt; &gt; The more energy something has, the more heat it\n&gt; &gt; usually has. Only at 0K in which anything is\n&gt; &gt; totally devoid of energy. To have negative energy,\n&gt; &gt; one has to cool something below absolute zero.\n&gt; &gt; This is a physics impossibility (even though in\n&gt; &gt; the future, someone could succeed at this) as we\n&gt; &gt; all know it. Finding negative energy or below 0K\n&gt; &gt; temperatures will pave the way for whole new physics.\n&gt; &gt; Psychogamer64\n&gt; ================================================== ===================\n\nRight, on an ABSOLUTE temperature scale, one cannot\ncool ordinary matter below 0 Kelvin.\n\n&gt; This also has relevance to the question of the\n&gt; possibility of worm-holes or warp-fields. Producing\n&gt; these has been called impractical because of the\n&gt; large amount of negative energy required. But if the\n&gt; interpretation of what is "negative energy" is frame\n&gt; dependent, how can it be said that large amounts can\n&gt; not be produced?\n\nGood question, and the perfect opportunity to speculate\nwildly. Remember those virtually fluctuating energies\nin the vacuum? WHY is it that the Uncertainty Principle\nis only invoked to talk about fluctuations ABOVE the\nzero-level? It seems to me that fluctuations BELOW\nzero should be just as possible. All that is needed is\na tiny modification to the standard (Energy * Time) form\nof the Uncertainty equation, such that Planck\'s Constant\nis allowed to be a negative value. This is no worse an\nassumption than saying, "Special Relativity does not\nforbid tachyons from existing, if we can accept the\nnotion of imaginary mass." (Actually, negative mass\nshould be easier to accept than imaginary mass!)\n\nVirtual particles that pop into being whenever\nUncertainty goes negative will possess negative\nmass/energy, of course. One might EXPECT equal\nquantities of ordinary and negative virtual\nparticles in the vacuum. Their total AVERAGE\nenergy goes back down to Zero, so their total\ngravitational effect also goes to Zero, nicely\nwiping out Physics\' most embarrassing discrepancy.\n\nThere are other Good Things that come from accepting\nthe idea of negative mass/energy, and allowing the\nconsequences of such existence to permeate Physics.\nSome of those consequences can be found here:\nhttp://www.nemitz.net/vernon/BALANCD2.pdf\n\nFinally, negative Temperature, on an Absolute\ntemperature scale, is nothing more than the\nkinetic energy possessed by particles of\nnegative mass.\n\n</UL></PRE></font></td></tr></table></BODY><HTML>');"> <IMG SRC=/images/buttons/ip.gif BORDER=0 ALIGN=CENTER ALT="View this Usenet post in original ASCII form">&nbsp;&nbsp;View this Usenet post in original ASCII form </a></div><P></jabberwocky>Thanks for the replies, folks!
Sorry about my delay in responding; for a few days after I
posted my query, I never saw that it passed the moderator,
so gave up looking. Today I found it by accident.

> chronon (stephen@chronon.org) wrote:
> You ask why vacuum self-energy gives a repuslion rather
> than a gravitational attraction. My understanding of
> this is as follows: If the vacuum has energy then you
> need supply that energy to create more vacuum. Think
> of a piston in a sealed container – you have to do work
> to pull it out. In that case it's the external air
> pressure pushing, but you should imagine a case where
> the work has to be done simply to create more vacuum.
> This means that there is effectively a negative
> pressure in a vacuum with self-energy.

I do understand this, but it still does not make sense
in the context of the Universe. The expanding Universe
is creating more vacuum, right? The energy to do that
should be coming FROM that expansion. Next, if that
new vacuum is now a source of repulsion in the Universe,
causing acceleration and the creation of even more
vacuum, then what happened to Energy Conservation?

Finally, it is not clear that this "negative pressure
property of the vacuum" is something that must be
explained in terms of virtual particles popping into
the vacuum. Maybe the vacuum itself ("fabric of
space/time") is the culprit, and the virtual
particles are just doing their own thing,
independently and blamelessly.

On the other hand, if QM and GR are ever to be
merged, "blameless" may not be allowed.


rgregoryclark@yahoo.com (Robert Clark) wrote:
>
> I have a related question that I posed once to
> sci.physics:
> ================================================== =====
> Date: 1997/10/02
>
> I had some questions on the same theme. In regards
> to the quantum vacuum, aka zero-point energy, is this
> regarded as being negative energy simply because the
> classical vacuum itself is considered to have zero
> energy so anything "below" that must have negative
> energy?

It was my understanding that the zero-point energy was
positive and not negative! GR may want it to be
negative per preceding text above by chronon, but
QM never said that, so far as I know. And, in fact
my own Question is, IF QM SAYS THAT, THEN HOW????


> The 'virtual' particles of vacuum fluctuations are
> regarded to exist only for extremely short times.
> Is this the only physical difference between them and
> 'actual' particles?

To the best of my knowlegdge, that is the case. Virtual
particles exist on borrowed energy, but while they
exist, they are mostly normal. One exception (not to
exclude others) is the photon. An ordinary real photon
always has the same amount of energy. A virtual photon
does not need to vanish when its energy drops below a
certain point (as would, for example, a virtual W boson)
so its energy can be described as "decaying smoothly
with time" -- and the shape of this curve is identical
to that of the simple function 1/X. This of course is
why the virtual photons associated the EM Force can
go out to infinite range, while the Weak Force is
extremely range-limited.

> If it is, then wouldn't this depend on the frame of
> reference? In a strong grav. field, time will appear
> to run slow compared to our (approximate) inertial
> frame. So particles that were virtual in the strong
> grav. field would appear to us to be real particles
> and we could observe them.

Sorry, but the rate of our perception/measurment-ability
is identically slowed, in that grav field. So the
virtual particles will still remain unseen.

> This seems to be implied by both the phenomena of
> Hawking radiation and the Unruh effect. In Hawking
> radiation, a black hole will appear to radiate because
> virtual particles close to the event horizon can
> escape out of the vicinity of the black hole.

The hole loses mass/energy in that process, so every
escaping virtual particle is no longer virtual.

> In the Unruh effect an accelerated mirror will
> appear to radiate due to the virtual particles it
> encounters, and time for an accelerated frame is
> also regarded as slowed compared to ours. However,
> this implies that whether or not you regard particles
> as real or virtual depends on your frame.

In this case any virtual particles that become real
to an accelerating observer, will do so at the expense
of the observer's energy of motion.

> This creates problems for general relativity,
> because to compute the gravitational field within
> a region we need to include all the mass-energy in
> the region.

I'm pretty sure that when done, this leads to the
historic discrepancy ("worst embarassment in Physics")
between QM and GR. 50+ orders of magnitude!

> So for us, we would include these 'virtual'
> particles because to us they are actual. But in
> the strong grav. field the particles are virtual
> and are not observed; so the calculation of the
> grav. field for the region would be less.

It is the AVERAGE of their >0 temporary existence
that leads to the discrepancy. I think.

> This assumes that the only difference in 'virtual'
> particles is their extremely short time frames.
> So are there other physical differences? One
> possibility is the fact that they are assumed to
> be created in only particle-antiparticle pairs.
> Then a way out of the problem with GR would be if
> the particle created positive gravity and the
> antiparticle created negative gravity. So in
> both frames the result would be no net
> contribution. Of course, the idea that
> antimatter creates negative gravity is not the
> standard view. However, the gravitational
> effects of antimatter have not been precisely
> measured so this question is still open. There
> are experiments in the works to test this using
> antihydrogen so this should be resolved in the
> next few years. See the Physics FAQ, "Does
> Antimatter Fall Up or Down,"
> http://wwwhpcc.astro.washington.edu/mirrors/physicsfaq/grav_antimatter.html.

Antimatter will fall DOWN, and the logic is:
Remember that a \gamma ray can be converted
into a particle/antiparticle pair. The \gamma
ray consists of ordinary energy that ATTRACTS
gravitationally. Half that \gamma's energy
becomes the ordinary particle, which also
ATTRACTS gravitationally. The other half of
the \gamma becomes the antiparticle, and the
gravitational essence of that energy
has no reason to change. Electric charge
(and some oddball aspect of the Weak Force)
is the only difference between matter and
antimatter particles.

> Another possible resolution would be that
> we should always include the virtual energy
> in a region to compute its gravitational
> field. This would result in a marked
> increase for the calculated grav. field so
> I don't know if this is a workable solution.

No, by 50+ orders of magnitude :)

> Bob Clark
>
> Note: I checked the Physics FAQ article,
> "Below Absolute Zero - What Does Negative
> Temperature Mean?", and found that the
> question of negative temperature is a
> separate one from that of negative energy.
> So I changed the subject line of the post.

Yeah, ordinary negative temperatures are merely
values relative to some arbitrarily-specified
zero value.

> Psychogamer64 <psychogamer@juno.com> wrote:
> > I have found a reason why negative energy wouldn't
> > exist, or how you can drop temperatures below 0K.
> > I have studied physics books. Heat IS energy.
> > The more energy something has, the more heat it
> > usually has. Only at 0K in which anything is
> > totally devoid of energy. To have negative energy,
> > one has to cool something below absolute zero.
> > This is a physics impossibility (even though in
> > the future, someone could succeed at this) as we
> > all know it. Finding negative energy or below 0K
> > temperatures will pave the way for whole new physics.
> > Psychogamer64
> ================================================== ===================

Right, on an ABSOLUTE temperature scale, one cannot
cool ordinary matter below Kelvin.

> This also has relevance to the question of the
> possibility of worm-holes or warp-fields. Producing
> these has been called impractical because of the
> large amount of negative energy required. But if the
> interpretation of what is "negative energy" is frame
> dependent, how can it be said that large amounts can
> not be produced?

Good question, and the perfect opportunity to speculate
wildly. Remember those virtually fluctuating energies
in the vacuum? WHY is it that the Uncertainty Principle
is only invoked to talk about fluctuations ABOVE the
zero-level? It seems to me that fluctuations BELOW
zero should be just as possible. All that is needed is
a tiny modification to the standard (Energy * Time) form
of the Uncertainty equation, such that Planck's Constant
is allowed to be a negative value. This is no worse an
assumption than saying, "Special Relativity does not
forbid tachyons from existing, if we can accept the
notion of imaginary mass." (Actually, negative mass
should be easier to accept than imaginary mass!)

Virtual particles that pop into being whenever
Uncertainty goes negative will possess negative
mass/energy, of course. One might EXPECT equal
quantities of ordinary and negative virtual
particles in the vacuum. Their total AVERAGE
energy goes back down to Zero, so their total
gravitational effect also goes to Zero, nicely
wiping out Physics' most embarrassing discrepancy.

There are other Good Things that come from accepting
the idea of negative mass/energy, and allowing the
consequences of such existence to permeate Physics.
Some of those consequences can be found here:
http://www.nemitz.net/vernon/BALANCD2.pdf

Finally, negative Temperature, on an Absolute
temperature scale, is nothing more than the
kinetic energy possessed by particles of
negative mass.

Tim S
Aug6-04, 03:04 AM
<jabberwocky><div class="vbmenu_control"><a href="jabberwocky:;" onClick="newWindow=window.open('','usenetCode','toolbar=no, location=no,scrollbars=yes,resizable=yes,status=no ,width=650,height=400'); newWindow.document.write('<HTML><HEAD><TITLE>Usenet ASCII</TITLE></HEAD><BODY topmargin=0 leftmargin=0 BGCOLOR=#F1F1F1><table border=0 width=625><td bgcolor=midnightblue><font color=#F1F1F1>This Usenet message\'s original ASCII form: </font></td></tr><tr><td width=449><br><br><font face=courier><UL><PRE>on 04/08/2004 7:23 am, vernonner3voltazim at vnemitz@pinn.net wrote:\n\n&gt; Thanks for the replies, folks!\n&gt; Sorry about my delay in responding; for a few days after I\n&gt; posted my query, I never saw that it passed the moderator,\n&gt; so gave up looking. Today I found it by accident.\n&gt;\n&gt;&gt; chronon (stephen@chronon.org) wrote:\n&gt;&gt; You ask why vacuum self-energy gives a repuslion rather\n&gt;&gt; than a gravitational attraction. My understanding of\n&gt;&gt; this is as follows: If the vacuum has energy then you\n&gt;&gt; need supply that energy to create more vacuum. Think\n&gt;&gt; of a piston in a sealed container =96 you have to do work\n&gt;&gt; to pull it out. In that case it\'s the external air\n&gt;&gt; pressure pushing, but you should imagine a case where\n&gt;&gt; the work has to be done simply to create more vacuum.\n&gt;&gt; This means that there is effectively a negative\n&gt;&gt; pressure in a vacuum with self-energy.\n&gt;\n&gt; I do understand this, but it still does not make sense\n&gt; in the context of the Universe. The expanding Universe\n&gt; is creating more vacuum, right? The energy to do that\n&gt; should be coming FROM that expansion. Next, if that\n&gt; new vacuum is now a source of repulsion in the Universe,\n&gt; causing acceleration and the creation of even more\n&gt; vacuum, then what happened to Energy Conservation?\n\nWell spotted. Energy is not globally conserved in GR, in general.\n\nEnergy is, roughly, the rate that matter flows through spacetime in the\n\'time\' direction. Hence defining energy requires defining, at each point\n= of spacetime, which direction is the future and how far you have to go\nto advance one time unit.\n\nIn Newtonian and special-relativistic spacetimes, there are special\nobvio= us choices for time directions and rates, which all give a\nconserved energy (and differ from one another only by kinetic energy).\nIn general relativi= ty, things are trickier. In what one might call\n\'somewhat nice\' spacetimes yo= u can define time in such a way that you\ncan take a global snapshot of spacetime at any given time, giving you\nspace at that time. Then as you trace time, you go through a succession\nof spatial slices, and that way y= ou cover the whole of spacetime\n(once). (\'Somewhat nice\' is roughly equivale= nt to the technical\ncondition \'globally hyperbolic\'.) In _really_ nice spacetimes, these\nspatial slices all have exactly the same geometry. Thes= e are the\n\'static\' spacetimes. You only get energy conservation in static\nspacetimes, and then only if you use the right definition of time\n(spatia= l slices have unchanging geometry).\n\nThe Big Bang (\'Friedman-Robertson-Walker\') spacetimes aren\'t like this.\nThere is an obvious special definition of time for them, but with that\ndefinition, space is expanding, so its geometry isn\'t preserved. Other\ndefinitions of time aren\'t so nice and also give changing spatial\ngeometr= y. So energy isn\'t conserved globally in Big Bang universes.\n\n(Energy in GR is always conserved _locally_, though, i.e. in a\nsufficient= ly small region, in which total curvature is negligible.)\n\n&lt;snipping the rest, because there\'s Too Much of it to look at.&gt;\n\nTim\n\n</UL></PRE></font></td></tr></table></BODY><HTML>');"> <IMG SRC=/images/buttons/ip.gif BORDER=0 ALIGN=CENTER ALT="View this Usenet post in original ASCII form">&nbsp;&nbsp;View this Usenet post in original ASCII form </a></div><P></jabberwocky>on 04/08/2004 7:23 am, vernonner3voltazim at vnemitz@pinn.net wrote:

> Thanks for the replies, folks!
> Sorry about my delay in responding; for a few days after I
> posted my query, I never saw that it passed the moderator,
> so gave up looking. Today I found it by accident.
>
>> chronon (stephen@chronon.org) wrote:
>> You ask why vacuum self-energy gives a repuslion rather
>> than a gravitational attraction. My understanding of
>> this is as follows: If the vacuum has energy then you
>> need supply that energy to create more vacuum. Think
>> of a piston in a sealed container =96 you have to do work
>> to pull it out. In that case it's the external air
>> pressure pushing, but you should imagine a case where
>> the work has to be done simply to create more vacuum.
>> This means that there is effectively a negative
>> pressure in a vacuum with self-energy.
>
> I do understand this, but it still does not make sense
> in the context of the Universe. The expanding Universe
> is creating more vacuum, right? The energy to do that
> should be coming FROM that expansion. Next, if that
> new vacuum is now a source of repulsion in the Universe,
> causing acceleration and the creation of even more
> vacuum, then what happened to Energy Conservation?

Well spotted. Energy is not globally conserved in GR, in general.

Energy is, roughly, the rate that matter flows through spacetime in the
'time' direction. Hence defining energy requires defining, at each point
= of spacetime, which direction is the future and how far you have to go
to advance one time unit.

In Newtonian and special-relativistic spacetimes, there are special
obvio= us choices for time directions and rates, which all give a
conserved energy (and differ from one another only by kinetic energy).
In general relativi= ty, things are trickier. In what one might call
'somewhat nice' spacetimes yo= u can define time in such a way that you
can take a global snapshot of spacetime at any given time, giving you
space at that time. Then as you trace time, you go through a succession
of spatial slices, and that way y= ou cover the whole of spacetime
(once). ('Somewhat nice' is roughly equivale= nt to the technical
condition 'globally hyperbolic'.) In _really_ nice spacetimes, these
spatial slices all have exactly the same geometry. Thes= e are the
'static' spacetimes. You only get energy conservation in static
spacetimes, and then only if you use the right definition of time
(spatia= l slices have unchanging geometry).

The Big Bang ('Friedman-Robertson-Walker') spacetimes aren't like this.
There is an obvious special definition of time for them, but with that
definition, space is expanding, so its geometry isn't preserved. Other
definitions of time aren't so nice and also give changing spatial
geometr= y. So energy isn't conserved globally in Big Bang universes.

(Energy in GR is always conserved _locally_, though, i.e. in a
sufficient= ly small region, in which total curvature is negligible.)

<snipping the rest, because there's Too Much of it to look at.>

Tim

vernonner3voltazim
Aug6-04, 03:04 AM
<jabberwocky><div class="vbmenu_control"><a href="jabberwocky:;" onClick="newWindow=window.open('','usenetCode','toolbar=no, location=no,scrollbars=yes,resizable=yes,status=no ,width=650,height=400'); newWindow.document.write('<HTML><HEAD><TITLE>Usenet ASCII</TITLE></HEAD><BODY topmargin=0 leftmargin=0 BGCOLOR=#F1F1F1><table border=0 width=625><td bgcolor=midnightblue><font color=#F1F1F1>This Usenet message\'s original ASCII form: </font></td></tr><tr><td width=449><br><br><font face=courier><UL><PRE>island &lt;island_in_the_stream@earthlink.net&gt; wrote:\n&gt; vernonner3voltazim wrote:\n&gt; &gt;\n&gt; &gt; Thanks for the replies, folks!\n&gt; &gt; Sorry about my delay in responding; for a few days after I\n&gt; &gt; posted my query, I never saw that it passed the moderator,\n&gt; &gt; so gave up looking. Today I found it by accident.\n&gt;\n&gt; &gt; &gt; chronon (stephen@chronon.org) wrote:\n&gt; &gt; &gt; You ask why vacuum self-energy gives a repuslion rather\n&gt; &gt; &gt; than a gravitational attraction. My understanding of\n&gt; &gt; &gt; this is as follows: If the vacuum has energy then you\n&gt; &gt; &gt; need supply that energy to create more vacuum. Think\n&gt; &gt; &gt; of a piston in a sealed container you have to do work\n&gt; &gt; &gt; to pull it out. In that case it\'s the external air\n&gt; &gt; &gt; pressure pushing, but you should imagine a case where\n&gt; &gt; &gt; the work has to be done simply to create more vacuum.\n&gt; &gt; &gt; This means that there is effectively a negative\n&gt; &gt; &gt; pressure in a vacuum with self-energy.\n&gt;\n&gt; &gt; I do understand this, but it still does not make sense\n&gt; &gt; in the context of the Universe. The expanding Universe\n&gt; &gt; is creating more vacuum, right? The energy to do that\n&gt; &gt; should be coming FROM that expansion. Next, if that\n&gt; &gt; new vacuum is now a source of repulsion in the Universe,\n&gt; &gt; causing acceleration and the creation of even more\n&gt; &gt; vacuum, then what happened to Energy Conservation?\n&gt;\n&gt;\n&gt; You don\'t have to "pull on the plunger to increase the\n&gt; vacuum". You can also increase the vacuum by way of\n&gt; condensation or compression, otherwise known as rarefaction.\n&gt;\n&gt; General Relativity says that gravitation is essentially\n&gt; curvature due to the energy contained in a region, so the\n&gt; condensation of enough vacuum energy over a region of space\n&gt; effectively converters this energy to the positve mass of\n&gt; particle pairs, and the \'departure\' is maintained in this\n&gt; manner. These departures will no longer produce negative\n&gt; curvature, so they cannot have negative mass, because the\n&gt; energy density of these particles does not represent the\n&gt; background density.\n\nI\'m sorry, but that is not clear. GR has never had much to\ndo with particle pairs, although perhaps you are referring\nto Hawking\'s efforts to combine some of QM with GR?\n\nAlso, I do not understand the phrase, "the \'departure\' is\nmaintained". I\'m sure it\'s because I\'m missing some sort\nof key background information. Fill me in, please!?\n\n&gt; Negative mass particles would make up the cosmological\n&gt; constant by way of -rho, which is entirely difffernt\n&gt; than observed antimatter particles, which do not.\n\nI think what you said about -rho can be true only if\nnegative mass particles outnumber ordinary-mass particles.\nUnless I need even more background info that I already\nthink. I\'m getting the impression that you think the\nsea of virtual particles in the vacuum has moments of\ngreater and lesser density, and that that leads to\nvarious consequences -- EXCEPT that the sea ITSELF is\na consequence of Uncertainty. "greater and lesser\ndensity" then just refers to places where greater and\nlesser amounts of Uncertainty happen to be happening.\nNow, I do know that some of those Uncertain events\ncan influence/decrease other Uncertain events (per the\nCasimir effect), and I\'ve speculated that their may\nbe other Uncertain events than can influence/increase\nother Uncertain events (per Symmetry), but I don\'t\nsee this as being as complicated as you describe.\n\n&gt; Holes that get left in the vacuum are then a result of\n&gt; condenstion of energy that only has negative mass\n&gt; because it exists in a negative density state until\n&gt; the immense gravitational energy of a Black Hole or\n&gt; other high energy photon events result in an incease\n&gt; in uncertainty that cause vacuum fluctions which\n&gt; enables the creation process.\n\nI have several problems with what you wrote there.\n"Holes that get left in the vacuum"??? This sounds\nlike you are trying to Conserve Energy in SPITE of\nthe Uncertainty Principle, which allows minor\ntemporary violations. Thus, no holes would be left\nin the vacuum, when a pair of virtual particles pop\ninto temporary existence. Also, your phrase\n"an increase in uncertainty" is also problematic,\nbecause Uncertainty is not the "result" of anything.\nIt simply IS, a part of the fabric of Reality.\n\n&gt; The main difference between this and Dirac\'s Hole\n&gt; Theory is that BOTH both the electron as well as\n&gt; the anti-electron will leave REAL holes in the\n&gt; vacuum.\n\nSorry, I need your answers to the preceding issues\nbefore I can believe that.\n\n&gt; As with electric charge, the normal distribution of\n&gt; negative energy does not contribute to pair creation.\n&gt; Only departures from the normal distribution in a\n&gt; vacuum will isolate enough vacuum energy to produce\n&gt; virtual particle pairs. These pairs can be converted\n&gt; into real particles given enough energy, but they do\n&gt; not have -rho if they represent localized departures\n&gt; from the norm.\n\nAnd now I am getting the impression that you are trying\nto describe two "levels" of virtual particles, perhaps\nbecause you prefer Einstein\'s "God does not play dice"\nscenario. But the Bell inequality experiments have\nindicated that dice-play is the norm....\n\n&gt; In terms of the Entropy of a Black Hole, the emmited\n&gt; antielectron has the same gravitational properties\n&gt; as an electron and the electron has a greater chance\n&gt; for survival, (thus maintaining the departureo\n&gt; indefinitely), since it might be a long time before\n&gt; it meets an antiparticle if its counterpart\n&gt; antiparticle gets sucked into the black\n&gt; hole.\n\nThe event horizon of a black hole is a mathematically\nthin (zero thickness) boundary from which nothing can\nescape. So, in the case when a particle/antiparticle\npair pops into temporary existence, they are initially\nallowed to possess very high kinetic energies (near\nlight-speed). If a fluctuation of the event horizon\'s\nposition just happens to gobble just one of the two\nparticles, the connection between the pair is broken,\nsuch that they can no longer disappear in unison (the\ngobbled particle can\'t get out of the black hole).\nThe hole pays for its gobbling by giving up whatever\namount of mass/energy allows the ungobbled virtual\nparticle to become REAL, be it neutrino, electron,\nproton, etc (including any antiparticle). If the\nungobbled particle happens to be moving fast enough\nin the right direction, then it can escape the black\nhole completely. As you say, antiparticles have a\nhard time staying alive, in a universe full of ordinary\ntypes. But when they meet their opposite numbers and\nmutully annihilate, photons appear that ALSO may\ncontinue to escape from the black hole. Depending on\ndirection of travel, of course.\n\n&gt; There will be a negative energy contribution for\n&gt; each occupied state of positive energy as well as\n&gt; a negative energy contribution for each unoccupied\n&gt; state of negative energy, because negative pressure\n&gt; increases in proportion to the holes that the\n&gt; departures represent.\n\nI shall doubt that because negative * negative = positive.\nSo, if it takes negative to balance positive, then it\ntakes positive to balance negative.\n\n&gt; If there are no walls to the container, then the\n&gt; process described above will affect vacuum expansion\n&gt; while G will remain constant, because the increase\n&gt; in mass energy which occurs by way of condensation\n&gt; of vacuum energy, will immediately be offset by the\n&gt; described increase in negative pressure which\n&gt; necessarily occurs if negative mass particles have\n&gt; negative density, until they don\'t.\n\nHow can you say that about negative mass particles,\nwhen we have none on-hand to study?\n\n&gt; The subject goes right off the charts in terms of\n&gt; its depth, and here\'s a link that explains it all\n&gt; better, although I really haven\'t even scratched\n&gt; the surface there either.\n&gt;\n&gt; http://www.geocities.com/naturescience//index.html\n\nThanks, but it seems to have the same problems I\nmentioned above.\n\n(snip)\n\n&gt; Dirac\'s cosmological model is valid, if the sign of\n&gt; the mass indicates that the asymmetry that exists\n&gt; between the two classes of particles is due to the\n&gt; fact that the antiparticle exists in a negative\n&gt; energy state, by way of -rho and negative mass,\n&gt; until enough vacuum energy is condensed over an\n&gt; isolated area to achieve positive gravitational\n&gt; curvature.\n\nAs mentioned previously, you seem to be trying to\napply Conservation to Uncertain events.\n\n&gt; Particle theory says that for every fermion type\n&gt; there is another fermion type that has exactly\n&gt; the same mass as its counterpart particle,\n\nThose would be ordinary antiparticles!\n\n&gt; ... and negative mass and density particles explain\n&gt; this without jumping to the conclusion that particle\n&gt; theory is necessarily wrong because our\n&gt; observations don\'t seem to support this predicted\n&gt; symmetry.\n\n??? Again, how can you say that? We have no\nnegative mass particles on-hand to say much about\nhow they will behave. Sure, we can speculate that\n**IF** they existed, then it is reasonable that\nthey be similar to particles we already know well,\nand that their existence may be handy in solving\nvarious problems with Physics. But such handiness\nis not proof that they do exist.\n\nNow, here is something you might find interesting\nto think about. As you know, the Energy * Time\nrelation for Uncertainty lets any specific energy\nquantity waver temporarily. And you know that\nthe Momentum * Position relation is just as valid.\nWell, suppose you had a virtual-particle pair that\nconsisted of one ordinary electron and one equivalent\nparticle having negative mass:\nordinary e &lt;--- (pop) ---&gt; e neg-mass\nAfter figuring what is needed for this event, we\nfind that total mass that appeared is Zero, total\nkinetic energy that appeared is Zero, but the total\nmomentum that appeared is nonZero. This event,\nthen, could be the quantum consequence of the\nMomentum * Position relation for Uncertainty!\nThat popped momentum, of course, is not allowed to\npersist, so the pair of particles must vanish, the\nsame as an ordinary particle/anti-particle pair\nvanishes because their borrowed energy cannot persist.\n\n&gt; Symmetry is maintained if particles that are\n&gt; created from the energy of the vacuum, have\n&gt; negative mass and density before they are condensed\n&gt; into positive mass and density virtual particles,\n&gt; which can then be converted into real particles,\n&gt; given enough energy.\n\nAs I said before, you are making things too\ncomplicated.\n\n&gt; Negative energy and density are then generally\n&gt; maintained by the negative pressure component,\n&gt; so both virtual and real that are created will\n&gt; increase negative pressure via further\n&gt; rarefaction of the vacuum.\n\nThank you for trying to answer my Question that\nstarted this Thread. I apologize if great gaps\nin my knowledge are keeping me from understanding\nyou properly. As I said before, "Fill me in!"\n\n</UL></PRE></font></td></tr></table></BODY><HTML>');"> <IMG SRC=/images/buttons/ip.gif BORDER=0 ALIGN=CENTER ALT="View this Usenet post in original ASCII form">&nbsp;&nbsp;View this Usenet post in original ASCII form </a></div><P></jabberwocky>island <island_in_the_stream@earthlink.net> wrote:
> vernonner3voltazim wrote:
> >
> > Thanks for the replies, folks!
> > Sorry about my delay in responding; for a few days after I
> > posted my query, I never saw that it passed the moderator,
> > so gave up looking. Today I found it by accident.
>
> > > chronon (stephen@chronon.org) wrote:
> > > You ask why vacuum self-energy gives a repuslion rather
> > > than a gravitational attraction. My understanding of
> > > this is as follows: If the vacuum has energy then you
> > > need supply that energy to create more vacuum. Think
> > > of a piston in a sealed container you have to do work
> > > to pull it out. In that case it's the external air
> > > pressure pushing, but you should imagine a case where
> > > the work has to be done simply to create more vacuum.
> > > This means that there is effectively a negative
> > > pressure in a vacuum with self-energy.
>
> > I do understand this, but it still does not make sense
> > in the context of the Universe. The expanding Universe
> > is creating more vacuum, right? The energy to do that
> > should be coming FROM that expansion. Next, if that
> > new vacuum is now a source of repulsion in the Universe,
> > causing acceleration and the creation of even more
> > vacuum, then what happened to Energy Conservation?
>
>
> You don't have to "pull on the plunger to increase the
> vacuum". You can also increase the vacuum by way of
> condensation or compression, otherwise known as rarefaction.
>
> General Relativity says that gravitation is essentially
> curvature due to the energy contained in a region, so the
> condensation of enough vacuum energy over a region of space
> effectively converters this energy to the positve mass of
> particle pairs, and the 'departure' is maintained in this
> manner. These departures will no longer produce negative
> curvature, so they cannot have negative mass, because the
> energy density of these particles does not represent the
> background density.

I'm sorry, but that is not clear. GR has never had much to
do with particle pairs, although perhaps you are referring
to Hawking's efforts to combine some of QM with GR?

Also, I do not understand the phrase, "the 'departure' is
maintained". I'm sure it's because I'm missing some sort
of key background information. Fill me in, please!?

> Negative mass particles would make up the cosmological
> constant by way of -\rho, which is entirely difffernt
> than observed antimatter particles, which do not.

I think what you said about -\rho can be true only if
negative mass particles outnumber ordinary-mass particles.
Unless I need even more background info that I already
think. I'm getting the impression that you think the
sea of virtual particles in the vacuum has moments of
greater and lesser density, and that that leads to
various consequences -- EXCEPT that the sea ITSELF is
a consequence of Uncertainty. "greater and lesser
density" then just refers to places where greater and
lesser amounts of Uncertainty happen to be happening.
Now, I do know that some of those Uncertain events
can influence/decrease other Uncertain events (per the
Casimir effect), and I've speculated that their may
be other Uncertain events than can influence/increase
other Uncertain events (per Symmetry), but I don't
see this as being as complicated as you describe.

> Holes that get left in the vacuum are then a result of
> condenstion of energy that only has negative mass
> because it exists in a negative density state until
> the immense gravitational energy of a Black Hole or
> other high energy photon events result in an incease
> in uncertainty that cause vacuum fluctions which
> enables the creation process.

I have several problems with what you wrote there.
"Holes that get left in the vacuum"??? This sounds
like you are trying to Conserve Energy in SPITE of
the Uncertainty Principle, which allows minor
temporary violations. Thus, no holes would be left
in the vacuum, when a pair of virtual particles pop
into temporary existence. Also, your phrase
"an increase in uncertainty" is also problematic,
because Uncertainty is not the "result" of anything.
It simply IS, a part of the fabric of Reality.

> The main difference between this and Dirac's Hole
> Theory is that BOTH both the electron as well as
> the anti-electron will leave REAL holes in the
> vacuum.

Sorry, I need your answers to the preceding issues
before I can believe that.

> As with electric charge, the normal distribution of
> negative energy does not contribute to pair creation.
> Only departures from the normal distribution in a
> vacuum will isolate enough vacuum energy to produce
> virtual particle pairs. These pairs can be converted
> into real particles given enough energy, but they do
> not have -\rho if they represent localized departures
> from the norm.

And now I am getting the impression that you are trying
to describe two "levels" of virtual particles, perhaps
because you prefer Einstein's "God does not play dice"
scenario. But the Bell inequality experiments have
indicated that dice-play is the norm....

> In terms of the Entropy of a Black Hole, the emmited
> antielectron has the same gravitational properties
> as an electron and the electron has a greater chance
> for survival, (thus maintaining the departureo
> indefinitely), since it might be a long time before
> it meets an antiparticle if its counterpart
> antiparticle gets sucked into the black
> hole.

The event horizon of a black hole is a mathematically
thin (zero thickness) boundary from which nothing can
escape. So, in the case when a particle/antiparticle
pair pops into temporary existence, they are initially
allowed to possess very high kinetic energies (near
light-speed). If a fluctuation of the event horizon's
position just happens to gobble just one of the two
particles, the connection between the pair is broken,
such that they can no longer disappear in unison (the
gobbled particle can't get out of the black hole).
The hole pays for its gobbling by giving up whatever
amount of mass/energy allows the ungobbled virtual
particle to become REAL, be it neutrino, electron,
proton, etc (including any antiparticle). If the
ungobbled particle happens to be moving fast enough
in the right direction, then it can escape the black
hole completely. As you say, antiparticles have a
hard time staying alive, in a universe full of ordinary
types. But when they meet their opposite numbers and
mutully annihilate, photons appear that ALSO may
continue to escape from the black hole. Depending on
direction of travel, of course.

> There will be a negative energy contribution for
> each occupied state of positive energy as well as
> a negative energy contribution for each unoccupied
> state of negative energy, because negative pressure
> increases in proportion to the holes that the
> departures represent.

I shall doubt that because negative * negative = positive.
So, if it takes negative to balance positive, then it
takes positive to balance negative.

> If there are no walls to the container, then the
> process described above will affect vacuum expansion
> while G will remain constant, because the increase
> in mass energy which occurs by way of condensation
> of vacuum energy, will immediately be offset by the
> described increase in negative pressure which
> necessarily occurs if negative mass particles have
> negative density, until they don't.

How can you say that about negative mass particles,
when we have none on-hand to study?

> The subject goes right off the charts in terms of
> its depth, and here's a link that explains it all
> better, although I really haven't even scratched
> the surface there either.
>
> http://www.geocities.com/naturescience//index.html

Thanks, but it seems to have the same problems I
mentioned above.

(snip)

> Dirac's cosmological model is valid, if the sign of
> the mass indicates that the asymmetry that exists
> between the two classes of particles is due to the
> fact that the antiparticle exists in a negative
> energy state, by way of -\rho and negative mass,
> until enough vacuum energy is condensed over an
> isolated area to achieve positive gravitational
> curvature.

As mentioned previously, you seem to be trying to
apply Conservation to Uncertain events.

> Particle theory says that for every fermion type
> there is another fermion type that has exactly
> the same mass as its counterpart particle,

Those would be ordinary antiparticles!

> ... and negative mass and density particles explain
> this without jumping to the conclusion that particle
> theory is necessarily wrong because our
> observations don't seem to support this predicted
> symmetry.

??? Again, how can you say that? We have no
negative mass particles on-hand to say much about
how they will behave. Sure, we can speculate that
**IF** they existed, then it is reasonable that
they be similar to particles we already know well,
and that their existence may be handy in solving
various problems with Physics. But such handiness
is not proof that they do exist.

Now, here is something you might find interesting
to think about. As you know, the Energy * Time
relation for Uncertainty lets any specific energy
quantity waver temporarily. And you know that
the Momentum * Position relation is just as valid.
Well, suppose you had a virtual-particle pair that
consisted of one ordinary electron and one equivalent
particle having negative mass:
ordinary e <--- (pop) ---> e neg-mass
After figuring what is needed for this event, we
find that total mass that appeared is Zero, total
kinetic energy that appeared is Zero, but the total
momentum that appeared is nonZero. This event,
then, could be the quantum consequence of the
Momentum * Position relation for Uncertainty!
That popped momentum, of course, is not allowed to
persist, so the pair of particles must vanish, the
same as an ordinary particle/anti-particle pair
vanishes because their borrowed energy cannot persist.

> Symmetry is maintained if particles that are
> created from the energy of the vacuum, have
> negative mass and density before they are condensed
> into positive mass and density virtual particles,
> which can then be converted into real particles,
> given enough energy.

As I said before, you are making things too
complicated.

> Negative energy and density are then generally
> maintained by the negative pressure component,
> so both virtual and real that are created will
> increase negative pressure via further
> rarefaction of the vacuum.

Thank you for trying to answer my Question that
started this Thread. I apologize if great gaps
in my knowledge are keeping me from understanding
you properly. As I said before, "Fill me in!"

vernonner3voltazim
Aug7-04, 05:06 PM
<jabberwocky><div class="vbmenu_control"><a href="jabberwocky:;" onClick="newWindow=window.open('','usenetCode','toolbar=no, location=no,scrollbars=yes,resizable=yes,status=no ,width=650,height=400'); newWindow.document.write('<HTML><HEAD><TITLE>Usenet ASCII</TITLE></HEAD><BODY topmargin=0 leftmargin=0 BGCOLOR=#F1F1F1><table border=0 width=625><td bgcolor=midnightblue><font color=#F1F1F1>This Usenet message\'s original ASCII form: </font></td></tr><tr><td width=449><br><br><font face=courier><UL><PRE>Tim S &lt;Tim@timsilverman.demon.co.uk&gt; wrote:\n&gt; &gt; vernonner3voltazim at vnemitz@pinn.net wrote:\n&gt;\n&gt; &gt; Thanks for the replies, folks!\n&gt; &gt; Sorry about my delay in responding; for a few days after I\n&gt; &gt; posted my query, I never saw that it passed the moderator,\n&gt; &gt; so gave up looking. Today I found it by accident.\n&gt; &gt;\n&gt; &gt; &gt; chronon (stephen@chronon.org) wrote:\n&gt; &gt; &gt; You ask why vacuum self-energy gives a repuslion rather\n&gt; &gt; &gt; than a gravitational attraction. My understanding of\n&gt; &gt; &gt; this is as follows: If the vacuum has energy then you\n&gt; &gt; &gt; need supply that energy to create more vacuum. Think\n&gt; &gt; &gt; of a piston in a sealed container =96 you have to do work\n&gt; &gt; &gt; to pull it out. In that case it\'s the external air\n&gt; &gt; &gt; pressure pushing, but you should imagine a case where\n&gt; &gt; &gt; the work has to be done simply to create more vacuum.\n&gt; &gt; &gt; This means that there is effectively a negative\n&gt; &gt; &gt; pressure in a vacuum with self-energy.\n&gt; &gt;\n&gt; &gt; I do understand this, but it still does not make sense\n&gt; &gt; in the context of the Universe. The expanding Universe\n&gt; &gt; is creating more vacuum, right? The energy to do that\n&gt; &gt; should be coming FROM that expansion. Next, if that\n&gt; &gt; new vacuum is now a source of repulsion in the Universe,\n&gt; &gt; causing acceleration and the creation of even more\n&gt; &gt; vacuum, then what happened to Energy Conservation?\n&gt;\n&gt; Well spotted. Energy is not globally conserved in GR, in general.\n\nIs that good or bad? I see what you wrote below about local\nenergy conservation, but this bothers me, like physicists\nhave been sitting on some dirty little secret. Certainly I\ndon\'t recall hearing about this before. The Big Bang itself,\nand any naked singularity that might have persisted afterware,\nsure, they are conservation violations. But GR as a whole???\n(see below)\n\n&gt; Energy is, roughly, the rate that matter flows through\n&gt; spacetime in the \'time\' direction. Hence defining energy\n&gt; requires defining, at each point of spacetime, which\n&gt; direction is the future and how far you have to go to\n&gt; advance one time unit.\n&gt;\n&gt; In Newtonian and special-relativistic spacetimes, there\n&gt; are special obvious choices for time directions and rates,\n&gt; which all give a conserved energy (and differ from one\n&gt; another only by kinetic energy). In general relativity,\n&gt; things are trickier. In what one might call \'somewhat nice\'\n&gt; spacetimes you can define time in such a way that you can\n&gt; take a global snapshot of spacetime at any given time,\n&gt; giving you space at that time. Then as you trace time, you\n&gt; go through a succession of spatial slices, and that way\n&gt; you cover the whole of spacetime (once). (\'Somewhat nice\'\n&gt; is roughly equivalent to the technical condition\n&gt; \'globally hyperbolic\'.) In _really_ nice spacetimes,\n&gt; these spatial slices all have exactly the same geometry.\n&gt; These are the \'static\' spacetimes. You only get energy\n&gt; conservation in static spacetimes, and then only if you\n&gt; use the right definition of time (spatial slices have\n&gt; unchanging geometry).\n\nInteresting!\n\n&gt; The Big Bang (\'Friedman-Robertson-Walker\') spacetimes\n&gt; aren\'t like this. There is an obvious special definition\n&gt; of time for them, but with that definition, space is\n&gt; expanding, so its geometry isn\'t preserved. Other\n&gt; definitions of time aren\'t so nice and also give changing\n&gt; spatial geometry. So energy isn\'t conserved globally\n&gt; in Big Bang universes.\n\nOK, I guess the thing to question is, "Just how sure are the\nGR theorists that Space is part of the Bang?" That is, they\nhave no trouble talking about "curved space" (although often\nphrased as "curved space-time"), and any decent mathematician\nknows that multidimensional geometry has nice points of\nconsistency among the descriptions of 2D "space", 3D space,\n4D, space, and so on. SO, if the Universe PRIOR to the BB\nwas just a big empty 4D space, then all the Bang really did\nwas just push a lot of stuff through a region of that\npreviously-existing hypervolume, and no new space needs to\nhave ever been created. Except for the BB itself and any\npersisting naked singularity, would a form of GR that used\nthis model include global energy conservation?\n\n&gt; (Energy in GR is always conserved _locally_, though,\n&gt; i.e. in a sufficient ly small region, in which total\n&gt; curvature is negligible.)\n\nWell, that just means that if we want to survive the\nHeat Death of the Universe, all we need is a really\nreally really really really really really really really\nBIG perpetual motion machine!\n\nThanks!!!!\n\n</UL></PRE></font></td></tr></table></BODY><HTML>');"> <IMG SRC=/images/buttons/ip.gif BORDER=0 ALIGN=CENTER ALT="View this Usenet post in original ASCII form">&nbsp;&nbsp;View this Usenet post in original ASCII form </a></div><P></jabberwocky>Tim S <Tim@timsilverman.demon.co.uk> wrote:
> > vernonner3voltazim at vnemitz@pinn.net wrote:
>
> > Thanks for the replies, folks!
> > Sorry about my delay in responding; for a few days after I
> > posted my query, I never saw that it passed the moderator,
> > so gave up looking. Today I found it by accident.
> >
> > > chronon (stephen@chronon.org) wrote:
> > > You ask why vacuum self-energy gives a repuslion rather
> > > than a gravitational attraction. My understanding of
> > > this is as follows: If the vacuum has energy then you
> > > need supply that energy to create more vacuum. Think
> > > of a piston in a sealed container =96 you have to do work
> > > to pull it out. In that case it's the external air
> > > pressure pushing, but you should imagine a case where
> > > the work has to be done simply to create more vacuum.
> > > This means that there is effectively a negative
> > > pressure in a vacuum with self-energy.
> >
> > I do understand this, but it still does not make sense
> > in the context of the Universe. The expanding Universe
> > is creating more vacuum, right? The energy to do that
> > should be coming FROM that expansion. Next, if that
> > new vacuum is now a source of repulsion in the Universe,
> > causing acceleration and the creation of even more
> > vacuum, then what happened to Energy Conservation?
>
> Well spotted. Energy is not globally conserved in GR, in general.

Is that good or bad? I see what you wrote below about local
energy conservation, but this bothers me, like physicists
have been sitting on some dirty little secret. Certainly I
don't recall hearing about this before. The Big Bang itself,
and any naked singularity that might have persisted afterware,
sure, they are conservation violations. But GR as a whole???
(see below)

> Energy is, roughly, the rate that matter flows through
> spacetime in the 'time' direction. Hence defining energy
> requires defining, at each point of spacetime, which
> direction is the future and how far you have to go to
> advance one time unit.
>
> In Newtonian and special-relativistic spacetimes, there
> are special obvious choices for time directions and rates,
> which all give a conserved energy (and differ from one
> another only by kinetic energy). In general relativity,
> things are trickier. In what one might call 'somewhat nice'
> spacetimes you can define time in such a way that you can
> take a global snapshot of spacetime at any given time,
> giving you space at that time. Then as you trace time, you
> go through a succession of spatial slices, and that way
> you cover the whole of spacetime (once). ('Somewhat nice'
> is roughly equivalent to the technical condition
> 'globally hyperbolic'.) In _really_ nice spacetimes,
> these spatial slices all have exactly the same geometry.
> These are the 'static' spacetimes. You only get energy
> conservation in static spacetimes, and then only if you
> use the right definition of time (spatial slices have
> unchanging geometry).

Interesting!

> The Big Bang ('Friedman-Robertson-Walker') spacetimes
> aren't like this. There is an obvious special definition
> of time for them, but with that definition, space is
> expanding, so its geometry isn't preserved. Other
> definitions of time aren't so nice and also give changing
> spatial geometry. So energy isn't conserved globally
> in Big Bang universes.

OK, I guess the thing to question is, "Just how sure are the
GR theorists that Space is part of the Bang?" That is, they
have no trouble talking about "curved space" (although often
phrased as "curved space-time"), and any decent mathematician
knows that multidimensional geometry has nice points of
consistency among the descriptions of 2D "space", 3D space,
4D, space, and so on. SO, if the Universe PRIOR to the BB
was just a big empty 4D space, then all the Bang really did
was just push a lot of stuff through a region of that
previously-existing hypervolume, and no new space needs to
have ever been created. Except for the BB itself and any
persisting naked singularity, would a form of GR that used
this model include global energy conservation?

> (Energy in GR is always conserved _locally_, though,
> i.e. in a sufficient ly small region, in which total
> curvature is negligible.)

Well, that just means that if we want to survive the
Heat Death of the Universe, all we need is a really
really really really really really really really really
BIG perpetual motion machine!

Thanks!!!!