alistair
Jun29-04, 04:28 PM
<jabberwocky><div class="vbmenu_control"><a href="jabberwocky:;" onClick="newWindow=window.open('','usenetCode','toolbar=no, location=no,scrollbars=yes,resizable=yes,status=no ,width=650,height=400'); newWindow.document.write('<HTML><HEAD><TITLE>Usenet ASCII</TITLE></HEAD><BODY topmargin=0 leftmargin=0 BGCOLOR=#F1F1F1><table border=0 width=625><td bgcolor=midnightblue><font color=#F1F1F1>This Usenet message\'s original ASCII form: </font></td></tr><tr><td width=449><br><br><font face=courier><UL><PRE>Is the gravitational force acting on a particle of mass m, on the\nsurface of a sphere of radius 10^24 metres and with a mass of 10^52\nkg given by\nG x10^52 m / (10^24 ) ^ 1/2 - the Newtonian value - or is the mass\ndensity high enough for general relativity to be required to get a\nsensible result?\n\n[Moderator\'s note: Presumably, you meant 2 rather than 1/2 in the\nexponent. In this context, the requirement for Newtonian gravity to\nbe a good approximation is that the radius be much greater than G m /\nc^2. If I\'ve done the arithmetic right, that does not appear to be\nthe case here, so Newtonian gravity is not adequate. -TB]\n</UL></PRE></font></td></tr></table></BODY><HTML>');"> <IMG SRC=/images/buttons/ip.gif BORDER=0 ALIGN=CENTER ALT="View this Usenet post in original ASCII form"> View this Usenet post in original ASCII form </a></div><P></jabberwocky>Is the gravitational force acting on a particle of mass m, on the
surface of a sphere of radius 10^24 metres and with a mass of 10^52
kg given by
G x10^52 m / (10^24 ) ^ 1/2 - the Newtonian value - or is the mass
density high enough for general relativity to be required to get a
sensible result?
[Moderator's note: Presumably, you meant 2 rather than 1/2 in the
exponent. In this context, the requirement for Newtonian gravity to
be a good approximation is that the radius be much greater than G m /
c^2. If I've done the arithmetic right, that does not appear to be
the case here, so Newtonian gravity is not adequate. -TB]
surface of a sphere of radius 10^24 metres and with a mass of 10^52
kg given by
G x10^52 m / (10^24 ) ^ 1/2 - the Newtonian value - or is the mass
density high enough for general relativity to be required to get a
sensible result?
[Moderator's note: Presumably, you meant 2 rather than 1/2 in the
exponent. In this context, the requirement for Newtonian gravity to
be a good approximation is that the radius be much greater than G m /
c^2. If I've done the arithmetic right, that does not appear to be
the case here, so Newtonian gravity is not adequate. -TB]