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Keval
Sep26-09, 03:05 PM
dt=\frac{1}{g-kv^2}dv
Need help to solve this, trying to find the time that a sphere takes to hit the ground.

so far i multiplied by -1 then tried subbing in kv^2=sin\theta but im getting nowhere with that method, can someone help me with a step by step method or give me the correct substitution

tiny-tim
Sep26-09, 04:10 PM
Duplicate of this thread (http://www.physicsforums.com/showthread.php?p=2366448)