Bailey
Jul7-04, 05:54 PM
anyone know how to derive the epicycloid of 2 cusp?
the eq. are:
y=(a+b)sin(t) - b(sin(((a+b)t)/b)
x=(a+b)cos(t) - b(cos(((a+b)t)/b)
where " t " is deata (in radian)
srry....i kinda didn't get how to use those "code" to put it into symbol. :confused:
anyhoo....i kinda got stuck on the part " (a+b)/b "
not sure why its it like that.
the eq. are:
y=(a+b)sin(t) - b(sin(((a+b)t)/b)
x=(a+b)cos(t) - b(cos(((a+b)t)/b)
where " t " is deata (in radian)
srry....i kinda didn't get how to use those "code" to put it into symbol. :confused:
anyhoo....i kinda got stuck on the part " (a+b)/b "
not sure why its it like that.