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Physics_Student
Aug1-04, 12:42 PM
I'm having trouble with what should be a simple question!

Let a = (2,4,-2) and b = (4,-2,2)

I need to be able to express a as the sum of two vectors, one parallel to b and the other perpendicular to b.

Thing is, I haven't the foggiest idea where to start! Any ideas?

Thanks

Muzza
Aug1-04, 12:59 PM
The vector parallel to b is called the "projection of a onto b". There is a formula for it, and it should be covered in any basic book on linear algebra (at least in the cases of the vectors being in R^2 or R^3). proj(a, b) = (a.b)/(b.b) * b, (but obviously it's no good to just know the formula, so get yourself a book) ;).

TenaliRaman
Aug1-04, 01:20 PM
erm,
u mean the component of a parallel to b is "the projection of a onto b" right?

anyways as muzza said the parallel component of a comes as a projection of a onto b and the entire thing can be written as,
a = [(a.b)/b^2] b + (a - [(a.b)/b^2] b)

the first component is parallel to b and the second component is perpendicular to b.

-- AI

Muzza
Aug1-04, 01:24 PM
erm,
u mean the component of a parallel to b is "the projection of a onto b" right?


Yes, I figured that was understood.

Physics_Student
Aug1-04, 01:25 PM
Thanks for the speedy replies.

I get where the parallel component comes from, but I don't understand where the perpendicular component comes from?

Muzza
Aug1-04, 01:30 PM
Let a_p be the aforementioned vector parallel to b, and a_o be the perpendicular vector. Then a = a_p + a_o <=> a_o = a - a_p = a - (a.b)/(b.b) * b.

Physics_Student
Aug1-04, 01:33 PM
Thanks, that explained it very clearly. Can't believe I didn't notice it was that simple.

Thanks

aswinsp
Jan7-12, 10:38 AM
there should be some another method

aswinsp
Jan7-12, 10:59 AM
misread it

Ryan_m_b
Jan7-12, 11:27 AM
aswinsp thank you for your contribution but if you look at the time stamp above people's names you will see that this thread is 8 years old. Posting in such an old thread is called necroposting and is not allowed.