Expressing Vector a as the Sum of Two Vectors Parallel and Perpendicular to b

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Discussion Overview

The discussion revolves around expressing a vector, specifically vector a = (2,4,-2), as the sum of two vectors: one that is parallel to another vector b = (4,-2,2) and another that is perpendicular to b. The scope includes mathematical reasoning and vector decomposition in linear algebra.

Discussion Character

  • Mathematical reasoning
  • Technical explanation
  • Homework-related

Main Points Raised

  • One participant expresses confusion about how to start decomposing vector a into components parallel and perpendicular to vector b.
  • Another participant provides the formula for the projection of a onto b, indicating that it is a standard topic in linear algebra.
  • A clarification is made that the component of a parallel to b is indeed the projection of a onto b, and the decomposition can be expressed mathematically.
  • A participant seeks further understanding of how to derive the perpendicular component of a.
  • Another participant explains that the perpendicular vector can be found by subtracting the parallel component from vector a.
  • One participant suggests there may be alternative methods for achieving the same result.
  • A later reply notes that the thread is old, indicating a concern about posting in long-dormant discussions.

Areas of Agreement / Disagreement

Participants generally agree on the method of finding the parallel component through projection, but there is uncertainty regarding the understanding of the perpendicular component. Some participants suggest alternative methods, indicating that multiple approaches may exist.

Contextual Notes

Some mathematical steps and definitions may be assumed but are not explicitly stated, leading to potential gaps in understanding for those unfamiliar with vector projections.

Physics_Student
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I'm having trouble with what should be a simple question!

Let a = (2,4,-2) and b = (4,-2,2)

I need to be able to express a as the sum of two vectors, one parallel to b and the other perpendicular to b.

Thing is, I haven't the foggiest idea where to start! Any ideas?

Thanks
 
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The vector parallel to b is called the "projection of a onto b". There is a formula for it, and it should be covered in any basic book on linear algebra (at least in the cases of the vectors being in R^2 or R^3). proj(a, b) = (a.b)/(b.b) * b, (but obviously it's no good to just know the formula, so get yourself a book) ;).
 
erm,
u mean the component of a parallel to b is "the projection of a onto b" right?

anyways as muzza said the parallel component of a comes as a projection of a onto b and the entire thing can be written as,
a = [(a.b)/b^2] b + (a - [(a.b)/b^2] b)

the first component is parallel to b and the second component is perpendicular to b.

-- AI
 
erm,
u mean the component of a parallel to b is "the projection of a onto b" right?

Yes, I figured that was understood.
 
Thanks for the speedy replies.

I get where the parallel component comes from, but I don't understand where the perpendicular component comes from?
 
Let a_p be the aforementioned vector parallel to b, and a_o be the perpendicular vector. Then a = a_p + a_o <=> a_o = a - a_p = a - (a.b)/(b.b) * b.
 
Thanks, that explained it very clearly. Can't believe I didn't notice it was that simple.

Thanks
 
there should be some another method
 
Last edited:
misread it
 
  • #10
aswinsp thank you for your contribution but if you look at the time stamp above people's names you will see that this thread is 8 years old. Posting in such an old thread is called necroposting and is not allowed.
 

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