ƒ(x)
Mar2-10, 12:57 PM
So. I stumbled upon this brilliant little deuction; it is simply marvelous.
This can be used when anyone needs to find the acceleration due to grav. When opposed by normal force equal to the objects weight in the y direction.
net force = normal force(call it n) - mg*sinA = 0
n = mg*sinA
n/m = g*sinA
this is the tricky part, because n is one farther in the alphabet than m, n/m simplifies to a
so a = g*sinA
This can be used when anyone needs to find the acceleration due to grav. When opposed by normal force equal to the objects weight in the y direction.
net force = normal force(call it n) - mg*sinA = 0
n = mg*sinA
n/m = g*sinA
this is the tricky part, because n is one farther in the alphabet than m, n/m simplifies to a
so a = g*sinA