alistair
Aug7-04, 05:06 PM
<jabberwocky><div class="vbmenu_control"><a href="jabberwocky:;" onClick="newWindow=window.open('','usenetCode','toolbar=no, location=no,scrollbars=yes,resizable=yes,status=no ,width=650,height=400'); newWindow.document.write('<HTML><HEAD><TITLE>Usenet ASCII</TITLE></HEAD><BODY topmargin=0 leftmargin=0 BGCOLOR=#F1F1F1><table border=0 width=625><td bgcolor=midnightblue><font color=#F1F1F1>This Usenet message\'s original ASCII form: </font></td></tr><tr><td width=449><br><br><font face=courier><UL><PRE>By writing the length contraction equation\n\nL2 = L1 (1 - v^2/c^2)^1/2 as:\n\nL2 = L1 ( 1 - v^2 / c^2 + small constant)^1/2\n\nT ab still equals T ba in the stress energy tensor\nand the magnitude of the four momentum of a photon is still zero.\nOne can imagine a proton falling into a black hole and\nreaching the speed of light at the expected position of the\nsingularity -the proton keeping a finite diameter under\nthis transformation.\nWould this mean the singularity in a black hole does not exist?\nAlso using the classical angular momentum mvr for a spinning\nblack hole and (1 - v^2/c^2 + small constant)^1/2, I\ncalculated a maximum angular momentum of 10^42 for\na black hole of five solar masses.This compares well\nwith the value from general relativity for the maximum\nwhich is 10^41 (GM^2/c).\nLet me know if you\'d like to see the details of this\ncalculation.\n\n</UL></PRE></font></td></tr></table></BODY><HTML>');"> <IMG SRC=/images/buttons/ip.gif BORDER=0 ALIGN=CENTER ALT="View this Usenet post in original ASCII form"> View this Usenet post in original ASCII form </a></div><P></jabberwocky>By writing the length contraction equation
L2 = L1 (1 - v^2/c^2)^1/2[/itex] as:
L2 = L1 ( 1 - v^2 / c^2 + small [itex]constant)^1/2
T ab still equals T ba in the stress energy tensor
and the magnitude of the four momentum of a photon is still zero.
One can imagine a proton falling into a black hole and
reaching the speed of light at the expected position of the
singularity -the proton keeping a finite diameter under
this transformation.
Would this mean the singularity in a black hole does not exist?
Also using the classical angular momentum mvr for a spinning
black hole and (1 - v^2/c^2 + small constant)^1/2, I
calculated a maximum angular momentum of 10^42 for
a black hole of five solar masses.This compares well
with the value from general relativity for the maximum
which is 10^41 (GM^2/c).
Let me know if you'd like to see the details of this
calculation.
L2 = L1 (1 - v^2/c^2)^1/2[/itex] as:
L2 = L1 ( 1 - v^2 / c^2 + small [itex]constant)^1/2
T ab still equals T ba in the stress energy tensor
and the magnitude of the four momentum of a photon is still zero.
One can imagine a proton falling into a black hole and
reaching the speed of light at the expected position of the
singularity -the proton keeping a finite diameter under
this transformation.
Would this mean the singularity in a black hole does not exist?
Also using the classical angular momentum mvr for a spinning
black hole and (1 - v^2/c^2 + small constant)^1/2, I
calculated a maximum angular momentum of 10^42 for
a black hole of five solar masses.This compares well
with the value from general relativity for the maximum
which is 10^41 (GM^2/c).
Let me know if you'd like to see the details of this
calculation.