Hayden McGuinness
Aug7-04, 05:06 PM
<jabberwocky><div class="vbmenu_control"><a href="jabberwocky:;" onClick="newWindow=window.open('','usenetCode','toolbar=no, location=no,scrollbars=yes,resizable=yes,status=no ,width=650,height=400'); newWindow.document.write('<HTML><HEAD><TITLE>Usenet ASCII</TITLE></HEAD><BODY topmargin=0 leftmargin=0 BGCOLOR=#F1F1F1><table border=0 width=625><td bgcolor=midnightblue><font color=#F1F1F1>This Usenet message\'s original ASCII form: </font></td></tr><tr><td width=449><br><br><font face=courier><UL><PRE>Let us say that two polarized entangled beams of photons are produced\nsuch that phi= 1/SQRT[2]( |1:H>|2:V> + |1:V>|2:H>), that is, if a\nphoton in beam 1 is measured in the H=Horizontal polarization, then a\ncorresponding photon in beam 2 will be found upon measurement to be in\nthe V=Vertical polarization (they are of course spatially separated,\nsay beam 1 goes on path A while 2 goes on B). Now say I put a 45\ndegree polarization rotator in one of the paths, say A. Would this\n"change" beam 1 such that ALL (with no loss of intensity, with ideal\ncomponents) of the beam, when measured,\nyielded either |H> or |V>? And since they are entangled, would ALL of\nbeam 2 then always be measured to be in |V> or |H>, respectively? (If\nthis analysis is correct, would you be able to predict which\npolarizations the beams went in with certainty, or is it 50/50?)\n\nAlso, I am assuming that when no polarizing rotator is place in the\npath both beam 1 and 2 will be found upon measurement to be a mix of H\nand V polarized photons, with on average 50% in H and 50% in V.\n\n\n\nThank you for your time,\n\nHayden McGuinness\n\n</UL></PRE></font></td></tr></table></BODY><HTML>');"> <IMG SRC=/images/buttons/ip.gif BORDER=0 ALIGN=CENTER ALT="View this Usenet post in original ASCII form"> View this Usenet post in original ASCII form </a></div><P></jabberwocky>Let us say that two polarized entangled beams of photons are produced
such that \phi= 1/\SQRT[2]( |1:H>|2:V> + |1:V>|2:H>), that is, if a
photon in beam 1 is measured in the H=Horizontal polarization, then a
corresponding photon in beam 2 will be found upon measurement to be in
the V=Vertical polarization (they are of course spatially separated,
say beam 1 goes on path A while 2 goes on B). Now say I put a 45
degree polarization rotator in one of the paths, say A. Would this
"change" beam 1 such that ALL (with no loss of intensity, with ideal
components) of the beam, when measured,
yielded either |H> or |V>? And since they are entangled, would ALL of
beam 2 then always be measured to be in |V> or |H>, respectively? (If
this analysis is correct, would you be able to predict which
polarizations the beams went in with certainty, or is it 50/50?)
Also, I am assuming that when no polarizing rotator is place in the
path both beam 1 and 2 will be found upon measurement to be a mix of H
and V polarized photons, with on average 50% in H and 50% in V.
Thank you for your time,
Hayden McGuinness
such that \phi= 1/\SQRT[2]( |1:H>|2:V> + |1:V>|2:H>), that is, if a
photon in beam 1 is measured in the H=Horizontal polarization, then a
corresponding photon in beam 2 will be found upon measurement to be in
the V=Vertical polarization (they are of course spatially separated,
say beam 1 goes on path A while 2 goes on B). Now say I put a 45
degree polarization rotator in one of the paths, say A. Would this
"change" beam 1 such that ALL (with no loss of intensity, with ideal
components) of the beam, when measured,
yielded either |H> or |V>? And since they are entangled, would ALL of
beam 2 then always be measured to be in |V> or |H>, respectively? (If
this analysis is correct, would you be able to predict which
polarizations the beams went in with certainty, or is it 50/50?)
Also, I am assuming that when no polarizing rotator is place in the
path both beam 1 and 2 will be found upon measurement to be a mix of H
and V polarized photons, with on average 50% in H and 50% in V.
Thank you for your time,
Hayden McGuinness